Description
Vanya has a scales for weighing loads and weights of masses w0, w1, w2, ..., w100 grams where w is some integer not less than 2(exactly one weight of each nominal value). Vanya wonders whether he can weight an item with mass m using the given weights, if the weights can be put on both pans of the scales. Formally speaking, your task is to determine whether it is possible to place an item of massm and some weights on the left pan of the scales, and some weights on the right pan of the scales so that the pans of the scales were in balance.
Input
The first line contains two integers w, m (2 ≤ w ≤ 109, 1 ≤ m ≤ 109) — the number defining the masses of the weights and the mass of the item.
Output
Print word 'YES' if the item can be weighted and 'NO' if it cannot.
Sample Input
3 7
YES
100 99
YES
100 50
NO
Hint
Note to the first sample test. One pan can have an item of mass 7 and a weight of mass 3, and the second pan can have two weights of masses 9 and 1, correspondingly. Then 7 + 3 = 9 + 1.
Note to the second sample test. One pan of the scales can have an item of mass 99 and the weight of mass 1, and the second pan can have the weight of mass 100.
Note to the third sample test. It is impossible to measure the weight of the item in the manner described in the input.
1 #include <stdio.h> 2 #include <string.h> 3 int main() 4 { 5 int w,m; 6 int i,j,flg; 7 while(scanf("%d %d",&w,&m)!=EOF) 8 { 9 flg=1; 10 while(m) 11 { 12 int a=m%w; 13 if(a==1 || a==0) 14 { 15 m=m/w; 16 } 17 else if(a==w-1) 18 { 19 m=m/w+1; 20 } 21 else 22 { 23 flg=0; 24 break; 25 } 26 } 27 if(flg) 28 printf("YES "); 29 else 30 printf("NO "); 31 } 32 return 0; 33 }