到达每个ab的值的概率是相等的 都是1/(m+n)
听说hdu4586差不多的题
数学期望,Ex=n/(m+n)正确的之和+m/(m+n)*(错误的之和+Ex)
https://blog.csdn.net/xuxiaobo1234/article/details/89228118(上面公式化简结果一致)
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
int x = sc.nextInt();
while (x-- > 0) {
int n = sc.nextInt();
int m = sc.nextInt();
int y = sc.nextInt();
double sum = 0;
for (int i = 0; i < n; i++) {
sum += sc.nextInt();
}
double res1 = sum / (m + n);
sum = 0;
for (int i = 0; i < m; i++) {
sum += sc.nextInt();
}
double res2 = sum / (m + n);
double res = (res1 + res2) / (1 - (m * 1.0) / (m + n));
if (res <= y)
System.out.println("Go");
else
System.out.println("Wait");
}
}
}
}