暴力破解unix/linux平台上采用crypt加密的口令

# coding=utf-8

'''
暴力破解crypt模块加密的密码
'''

import crypt
import optparse

usage = 'Usage: %prog [optinos] -p password.txt -d dictionary.txt'
parser = optparse.OptionParser(usage,version=1.0)
parser.add_option('-p',dest='pFile',action='store',
                  help='加密后的口令存放文件')
parser.add_option('-d',dest='dFile',action='store',
                  help='字典文件')
(options,args) = parser.parse_args()

def dection_passwords(password):
   salt = password[:2]
   dfile = open(options.dFile)
   for word in dfile:
        word = word.strip('
')
        cryptWord = crypt.crypt(word,salt)
        if cryptWord == password:
            print '找到密码,密码是：',word
            return
   print '未找到密码！'
   return

def main():
   passfile = open(options.pFile)
   for password in passfile:
        password = password.strip('
')
        if password != '':
            dection_passwords(password)

if __name__ == '__main__':
   main()

运行后的结果是：

python ForceCrackCrypt.py -p /root/Desktop/password.txt -d /root/Desktop/dictionary.txt
找到密码,密码是： 123456
找到密码,密码是： 11111111
找到密码,密码是： abc123