482. License Key Formatting
Easy
You are given a license key represented as a string S which consists only alphanumeric character and dashes. The string is separated into N+1 groups by N dashes.
Given a number K, we would want to reformat the strings such that each group contains exactly K characters, except for the first group which could be shorter than K, but still must contain at least one character. Furthermore, there must be a dash inserted between two groups and all lowercase letters should be converted to uppercase.
Given a non-empty string S and a number K, format the string according to the rules described above.
Example 1:
Input: S = "5F3Z-2e-9-w", K = 4 Output: "5F3Z-2E9W" Explanation: The string S has been split into two parts, each part has 4 characters. Note that the two extra dashes are not needed and can be removed.
Example 2:
Input: S = "2-5g-3-J", K = 2 Output: "2-5G-3J" Explanation: The string S has been split into three parts, each part has 2 characters except the first part as it could be shorter as mentioned above.
Note:
- The length of string S will not exceed 12,000, and K is a positive integer.
- String S consists only of alphanumerical characters (a-z and/or A-Z and/or 0-9) and dashes(-).
- String S is non-empty.
package leetcode.easy; public class LicenseKeyFormatting { public String licenseKeyFormatting(String S, int K) { StringBuffer sb = new StringBuffer(); int count = 0; for (int i = S.length() - 1; i >= 0; i--) { char c = S.charAt(i); if (c != '-') { if (count > 0 && count % K == 0) { sb.append('-'); } sb.append(c); count++; } } return sb.reverse().toString().toUpperCase(); } @org.junit.Test public void test() { System.out.println(licenseKeyFormatting("5F3Z-2e-9-w", 4)); System.out.println(licenseKeyFormatting("2-5g-3-J", 2)); } }