PAT 00-自测1. 打印沙漏(20)

今天第一次在线（浙大PAT）刷算法题，折腾好几个小时后，终于成功了:)

c用的少，写起来好费力，将多个*拼接，就百度好久。下面再用其他语言试试。

#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <string.h>
int main(){
　　　　/*PAT 00-自测1. 打印沙漏(20)
	*2015.4.13
	*shaonian.ding
	*PATLink:http://www.patest.cn/contests/mooc-ds2015spring/00-%E8%87%AA%E6%B5%8B1
	*/	 

	int test = 1000;
	char cStar = '*';
	//scanf_s("%c", &cStar,1);
	scanf("%d %c", &test, &cStar);

	int temp = (test + 1) / 2;
	int n = (int)sqrt((double)temp);
	int i = n;
	
	for (i; i > 0; i--)
	{
		int numStar = 2 * (i - 1) + 1;
		char *star = (char *)calloc(numStar + 1, 1);
		char *space = (char *)calloc(n - i + 1, 1);
		char *lineStar = (char *)memset(star, cStar, numStar);
		char *lineSpace = (char *)memset(space, ' ', n - i);
		printf("%s%s
", space, lineStar);
		free(space);
		free(star);
	}
	int j = 2;
	for (j; j <= n; j++)
	{
		int numStar = 2 * (j - 1) + 1;
		char *star = (char *)calloc(numStar + 1, 1);
		char *space = (char *)calloc(n-j + 1, 1);
		char *lineStar = (char *)memset(star, cStar, numStar);
		char *lineSpace = (char *)memset(space, ' ', n - j);
		printf("%s%s
", space, lineStar);
		free(space);
		free(star);
	}
	printf("%d
", test - (2 * n * n - 1));
	getchar();
	return 0;
}