Unix时间戳

题目链接： http://exercise.acmcoder.com/online/online_judge_ques?ques_id=3356&konwledgeId=40

解题思路： 暴力枚举当前的年份，月份，天数。

#include <bits/stdc++.h>
using namespace std;

typedef long long LL;
const int MAXN=100005;
const LL MON7 = 1e9+7;
int d[][12]={31,28,31,30,31,30,31,31,30,31,30,31,
              31,29,31,30,31,30,31,31,30,31,30,31};

LL seconds;
LL days;
LL year, month, day;

bool isLeapYear(LL year)
{
    return (year%400==0 || year%4==0 && year%100!=0);
}

//LL searchYear(LL days)
//{
//
//}

void solve()
{
    days = seconds/24/60/60+1;
    year=1970;
    month=0;
    day=0;
    bool flags = isLeapYear(year);
    while (flags && days>366 || days>365)
    {
        ++year;
        days-=(flags?366:365);
        flags=isLeapYear(year);
    }
    while (days>d[flags][month]) days-=d[flags][month++];
    day=days;
    printf("%04lld %02lld %02lld
",year, month+1, day);
}

int main()
{
#ifndef ONLINE_JUDGE
    freopen("test.txt","r",stdin);
#endif // ONLINE_JUDGE
    int Case;
    //scanf("%d",&Case);
    while (scanf("%lld", &seconds)!=-1)
    {
        solve();
    }
    return 0;
}