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  • [BZOJ 3132] 上帝造题的七分钟

    [题目链接]

             https://www.lydsy.com/JudgeOnline/problem.php?id=3132

    [算法]

             二维树状数组

    [代码]

             

    #include<bits/stdc++.h>
    using namespace std;
    #define MAXN 2050
    
    int n,m,a,b,c,d;
    int delta;
    int bit[5][MAXN][MAXN];
    char op[5];
    
    inline int lowbit(int x)
    {
            return x & (-x);
    }
    inline void modify1(int x,int y,int val)
    {
            for (register int i = x; i <= n; i += lowbit(i))
            {
                    for (register int j = y; j <= m; j += lowbit(j))
                    {
                            bit[1][i][j] += val;    
                    }        
            }
    }
    inline void modify2(int x,int y,int val)
    {
            for (register int i = x; i <= n; i += lowbit(i))
            {
                    for (register int j = y; j <= m; j += lowbit(j))
                    {
                            bit[2][i][j] += val;    
                    }        
            }
    }
    inline void modify3(int x,int y,int val)
    {
            for (register int i = x; i <= n; i += lowbit(i))
            {
                    for (register int j = y; j <= m; j += lowbit(j))
                    {
                            bit[3][i][j] += val;    
                    }        
            }
    }
    inline void modify4(int x,int y,int val)
    {
            for (register int i = x; i <= n; i += lowbit(i))
            {
                    for (register int j = y; j <= m; j += lowbit(j))
                    {
                            bit[4][i][j] += val;    
                    }        
            }
    }
    inline int query1(int x,int y)
    {
            int ret = 0;
            for (register int i = x; i >= 1; i -= lowbit(i))
            {
                    for (register int j = y; j >= 1; j -= lowbit(j))
                    {
                            ret += bit[1][i][j];
                    }
            }
            return ret;
    }
    inline int query2(int x,int y)
    {
            int ret = 0;
            for (register int i = x; i >= 1; i -= lowbit(i))
            {
                    for (register int j = y; j >= 1; j -= lowbit(j))
                    {
                            ret += bit[2][i][j];
                    }
            }
            return ret;
    }
    inline int query3(int x,int y)
    {
            int ret = 0;
            for (register int i = x; i >= 1; i -= lowbit(i))
            {
                    for (register int j = y; j >= 1; j -= lowbit(j))
                    {
                            ret += bit[3][i][j];
                    }
            }
            return ret;
    }
    inline int query4(int x,int y)
    {
            int ret = 0;
            for (register int i = x; i >= 1; i -= lowbit(i))
            {
                    for (register int j = y; j >= 1; j -= lowbit(j))
                    {
                            ret += bit[4][i][j];
                    }
            }
            return ret;
    }
    inline void Modify(int x,int y,int delta)
    {
            modify1(x,y,delta);        
            modify2(x,y,x * delta);
            modify3(x,y,y * delta);
            modify4(x,y,x * y * delta);
    }
    inline int Query(int x,int y)
    {
            int v1 = query1(x,y),v2 = query2(x,y),v3 = query3(x,y),v4 = query4(x,y);
            int ans1 = x * (v1 * y - v3 + v1);
            int ans2 = v2 * y - v4 + v2;
            int ans3 = v1 * y - v3 + v1;
            return ans1 - ans2 + ans3;
    }
    
    int main() 
    {
            
            scanf("%s%d%d",&op,&n,&m);
            while (scanf("%s",&op) != EOF)
            {
                    if (op[0] == 'L')
                    {
                            scanf("%d%d%d%d%d",&a,&b,&c,&d,&delta);
                            Modify(a,b,delta);
                            Modify(a,d + 1,-delta);
                            Modify(c + 1,b,-delta);
                            Modify(c + 1,d + 1,delta);            
                    }    else
                    {
                            scanf("%d%d%d%d",&a,&b,&c,&d);
                            printf("%d
    ",Query(c,d) - Query(a - 1,d) - Query(c,b - 1) + Query(a - 1,b - 1));
                    }
            }
            
            return 0;
        
    }
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  • 原文地址:https://www.cnblogs.com/evenbao/p/9503148.html
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