zoukankan      html  css  js  c++  java
  • 424. Longest Repeating Character Replacement

    Given a string s that consists of only uppercase English letters, you can perform at most k operations on that string.

    In one operation, you can choose any character of the string and change it to any other uppercase English character.

    Find the length of the longest sub-string containing all repeating letters you can get after performing the above operations.

    Note:
    Both the string's length and k will not exceed 104.

    Example 1:

    Input:
    s = "ABAB", k = 2
    
    Output:
    4
    
    Explanation:
    Replace the two 'A's with two 'B's or vice versa.
    

    Example 2:

    Input:
    s = "AABABBA", k = 1
    
    Output:
    4
    
    Explanation:
    Replace the one 'A' in the middle with 'B' and form "AABBBBA".
    The substring "BBBB" has the longest repeating letters, which is 4.

    sliding window

    time = O(n), space = O(1)

    class Solution {
        public int characterReplacement(String s, int k) {
            int[] count = new int[26];
            // maxCount: max # of unique characters in the current window
            int slow = 0, fast = 0, counter = 0, maxCount = 0, maxLen = 0;
            while(fast < s.length()) {
                count[s.charAt(fast) - 'A']++;
                maxCount = Math.max(maxCount, count[s.charAt(fast) - 'A']);
                fast++;
                
                // end - start - maxCount: # of characters that are NOT the character that occurs the most in the window
                while(fast - slow - maxCount > k) {
                    count[s.charAt(slow) - 'A']--;
                    slow++;
                }
                maxLen = Math.max(maxLen, fast - slow);
            }
            return maxLen;
        }
    }
  • 相关阅读:
    Django基础
    MySQL(索引)
    MySQL(进阶部分)
    MySQL(Python+ORM)
    JavaScript的对象
    abc
    Let's Encrypt,免费好用的 HTTPS 证书
    Java调试那点事
    Memcache mutex 设计模式
    从 Nginx 默认不压缩 HTTP/1.0 说起
  • 原文地址:https://www.cnblogs.com/fatttcat/p/11388112.html
Copyright © 2011-2022 走看看