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  • leetcode -- Validate Binary Search Tree

    Given a binary tree, determine if it is a valid binary search tree (BST).

    Assume a BST is defined as follows:

    • The left subtree of a node contains only nodes with keys less than the node's key.
    • The right subtree of a node contains only nodes with keys greater than the node's key.
    • Both the left and right subtrees must also be binary search trees.

    [解题思路]

    1.中序遍历BST得到的是一个有序的结果,遍历该结果如果出现前面数字比后面大的则说明不是BST

     1 /**
     2  * Definition for binary tree
     3  * public class TreeNode {
     4  *     int val;
     5  *     TreeNode left;
     6  *     TreeNode right;
     7  *     TreeNode(int x) { val = x; }
     8  * }
     9  */
    10 public class Solution {
    11     public boolean isValidBST(TreeNode root) {
    12         // Start typing your Java solution below
    13         // DO NOT write main() function
    14         if(root == null){
    15             return true;
    16         }
    17         ArrayList<Integer> elems = new ArrayList<Integer>();
    18         inOrderTraverse(root, elems);
    19         boolean result = true;
    20         for(int i = 1; i < elems.size(); i++){
    21             if(elems.get(i - 1) >= elems.get(i)){
    22                 result = false;
    23                 break;
    24             }
    25         }
    26         return result;
    27     }
    28     
    29     public void inOrderTraverse(TreeNode node, ArrayList<Integer> elems){
    30         if(node == null){
    31             return;
    32         }
    33         if(node.left != null){
    34             inOrderTraverse(node.left, elems);
    35         }
    36         elems.add(node.val);
    37         if(node.right != null){
    38             inOrderTraverse(node.right, elems);
    39         }
    40         
    41     }
    42 }

    2.判断一个tree是不是BST需要满足如下几点:

    a.左子树的节点都小于当前node值

    b.右子树的节点都大于当前node值

    这里通过传递每个节点的上下界来判断该子节点是否符合要求

     1 public boolean isValidBST(TreeNode root) {
     2         // Start typing your Java solution below
     3         // DO NOT write main() function
     4         return isBSTHelper(root, Integer.MIN_VALUE, Integer.MAX_VALUE);
     5     }
     6     
     7     public boolean isBSTHelper(TreeNode node, int low, int high){
     8         if(node == null){
     9             return true;
    10         }
    11         int value = node.val;
    12         if(low < value && value < high &&
    13             isBSTHelper(node.left, low, value) &&
    14             isBSTHelper(node.right, value, high)){
    15                 return true;
    16             } else {
    17                 return false;
    18             }
    19     }

     http://leetcode.com/2010/09/determine-if-binary-tree-is-binary.html

    http://tech-wonderland.net/blog/leetcode-validate-binary-search-tree.html

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  • 原文地址:https://www.cnblogs.com/feiling/p/3260967.html
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