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利用Java脚本实现弹出窗口后,按确定实现跳转
<!
DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"
>
<
HTML
>
<
HEAD
>
<
TITLE
>
利用Java脚本实现弹出窗口后,按确定实现跳转
</
TITLE
>
<
script
type
="text/javascript"
>
function
aa()
{
alert(
new
Date());
window.open(
"
http://www.baidu.com
"
,
"
_self
"
,
null
);
}
</
script
>
</
HEAD
>
<
BODY
>
<
input
type
="button"
value
="Go"
onclick
="aa();"
/>
</
BODY
>
</
HTML
>
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原文地址:https://www.cnblogs.com/flaaash/p/1075408.html
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