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  • Ajax_Jason 使用小Demo

    <!DOCTYPE html>
    <html lang="en">
    <head>
        <meta charset="UTF-8">
        <title>Title</title>
        <script src="js/jquery-2.1.0.min.js"></script>
        <script>
            $(function () {
                $("#username").blur(function () {
                    var user_name = $(this).val();
                    //发送ajax请求    1请求资源路径 重点注意!路径不需要写反斜杠 /  2参数{} 3回调函数:返回值调用的函数
                    $.get("findUserServlet",{username:user_name},function (data) {
    
                        //期望d返回的数据格式是:{“userExsit”: true ,“msg":"用户名存在"}
                                       //{“userExsit”: fase ,“msg":"用户名不存在"}
    
                        if(data.userExsit){
                            $("#user_").css("color","red");
                            $("#user_").html(data.msg);
                        }else {
                            $("#user_").html(data.msg);
                        }
                    },"json") //“json”_指定返回数据的格式,不然就会把返回的数据当做字符串格式,不会当做json对象格式! 那么就无法获取对应的值了
                              //或者在 服务器端指定MEMI类型: response.setContentType("application/json;charset=utf-8")
                });
            });
        </script>
    
    </head>
    <body>
        <form>
            <input type="text" id="username" name="username" placeholder="请输入用户名"><span id="user_"></span><br/>
            <input type="password" id="psd" name="psd" placeholder="请输入密码"><br/>
            <input type="submit" value="注册">
        </form>
    </body>
    </html>

    请求的服务端

    package servlet;
    
    import com.fasterxml.jackson.databind.ObjectMapper;
    
    import javax.servlet.ServletException;
    import javax.servlet.annotation.WebServlet;
    import javax.servlet.http.HttpServlet;
    import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServletResponse;
    import java.io.IOException;
    import java.util.HashMap;
    import java.util.Map;
    
    @WebServlet("/findUserServlet")
    public class FindUserServlet extends HttpServlet {
        protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
            doGet(request, response);
        }
    
        protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    
            //response.setContentType("text/html;charset=utf-8");
            response.setContentType("application/json;charset=utf-8");
    
    
            String username = request.getParameter("username");
            System.out.println(username);
            Map<String,Object> map = new HashMap<String,Object>();
    
            if(username.equals("tom")) {
                map.put("userExsit",true);
                map.put("msg","用户名存在");
            }else {
                map.put("userExsit",false);
                map.put("msg","用户名不存在");
            }
    
            //将其用JackSom工具 写成jason格式传输出去  使用前需要导入jackson的jar包
            ObjectMapper ob = new ObjectMapper();
            ob.writeValue(response.getWriter(),map);  //想要返回去的数据要客户端当做 json数据看待的话必须设置 response.setContentType("application/json;charset=utf-8")
                                                      //或者在客服端页面的ajax请求的数据类型写成 “json”
        }
    }
    坚持
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  • 原文地址:https://www.cnblogs.com/gaoSJ/p/13736930.html
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