基础练习

1.购物车

2.三级菜单

3.猜数字

4.打印进度条

python基础之购物车练习：

1.输入月薪打印商品列表，

2.选购商品，显示余额，

3.可随时退出，并打印所购商品及余额。

product_list = [
    ("iphone",5000),
    ("MacPro",10000),
    ("Book",120),
    ("bicycle",1000),
    ("TV",2000),
    ("washer",3000),
    ("pen",50)
]
shopping_list = []
salary = input("Input your salary : ")
if salary.isdigit():
    salary = int(salary)
    while True:
        for index,item in enumerate(product_list):
            print(index,item)
        user_choice = input("what do you want to buy,or enter q to leave: ")
        if user_choice.isdigit():
            user_choice = int(user_choice)
            if user_choice >= 0 and user_choice < len(product_list):
                p_item = product_list[user_choice]
                if salary >= p_item[1]:
                    shopping_list.append(p_item[0])
                    salary = salary-p_item[1]
                    print("add your choice into shoppingcart,your current balance is 33[31;1m%s33[0m." %salary)
                else:
                    print("you have money only 33[31;1m%s33[0m,can't payment"%salary)
            else:
                print("your choice is outof selection")
        elif user_choice == "q":
            print("-----shopping cart-----")
            for p in shopping_list:
                print(p)
            exit()
        else:
            print("invaild option")
else:
    print("Please input the digit")

python基础之简单版三级菜单：

data = {
    "北京":{},
    "福建":{
        "厦门":{
            "鼓浪屿":["日光岩","淑庄花园"],
            "思明区":["南普陀","厦门大学"],
            "湖里区":["湖里公园","保税区"]
        },
        "漳州":{},
        "泉州":{}
    },
    "广东":{}
}

exit_flag = False
while not exit_flag:
    for i in data:
        print(i)
    choice = input("what's your option1 :")
    if choice in data:
        while not exit_flag:
            for i2 in data[choice]:
                print(i2)
            choice2 = input("what's your option2 :")
            if choice2 in data[choice]:
                while not exit_flag:
                    for i3 in data[choice][choice2]:
                        print(i3)
                    choice3 = input("what's your option3 :")
                    if choice3 in data[choice][choice2]:
                        for i4 in  data[choice][choice2][choice3]:
                            print(i4)
                        last_1 = input("the last menu,enter b back:")
                        if last_1 == "b":
                            pass
                        elif last_1 == "q":
                            exit_flag = True
                    elif choice3 == "b":
                        break
                    elif choice3 == "q":
                        exit_flag =True
            elif choice2 == "b":
                break
            elif choice2 == "q":
                exit_flag =True
    elif choice == "q":
        exit_flag = True
    elif choice not in data:
        print("Please input the 33[1;31;40mRight33[0m option")

menu = {
    '北京': {
        '海淀': {
            '五道口': {
                'soho': {},
                '网易': {},
                'google': {}
            },
            '中关村': {
                '爱奇艺': {},
                '汽车之家': {},
                'youku': {},
            },
            '上地': {
                '百度': {},
            },
        },
        '昌平': {
            '沙河': {
                '老男孩': {},
                '北航': {},
            },
            '天通苑': {},
            '回龙观': {},
        },
        '朝阳': {},
        '东城': {},
    },
    '上海': {
        '闵行': {
            "人民广场": {
                '炸鸡店': {}
            }
        },
        '闸北': {
            '火车战': {
                '携程': {}
            }
        },
        '浦东': {},
    },
    '山东': {},
}

#堆栈的思想
# l = [menu]
# while l:
#     for key in l[-1]:
#         print(key)
#     k = input('input>>').strip()   # 北京
#     if k in l[-1].keys() and l[-1][k]:l.append(l[-1][k])
#     elif k == 'b':
#         l.pop()
#     elif k == 'q':
#         break

#递归的思想
def three_level_menu(menu):
    while True:
        for key in menu:
            print(key)
        k=input('>>>')
        if k=='q':return 'q'
        elif k=='b':break
        elif k in menu:
            ret=three_level_menu(menu[k])
            if ret=='q':return 'q'
three_level_menu(menu)

python基础之猜数字：

打印进度条

#first
import  time,sys
for i in range(10):
    sys.stdout.write("#")
    sys.stdout.flush()
    time.sleep(0.5)



#second
import time
for i in range(0,101,2):
    time.sleep(0.1)
    char_num = i//2   #打印多少个*    #
相当于seek(0) 即回到行首
    per_str = '
%s%% : %s
' % (i,'*' * char_num) if i==100 else '
%s%% : %s' %(i,'*' *char_num)
    print(per_str,end='',flush=True)
#progress Bar 专门做进度条的模块，可以研究一下