Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011
, so the function should return 3.
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Special thanks to @ts for adding this problem and creating all test cases.
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1 public class Solution { 2 // you need to treat n as an unsigned value 3 public int hammingWeight(int n) { 4 int count = 0; 5 // while(n/2 != 1){ 6 // if(n%2 == 1) count++; 7 // n /= 2; 8 // } 9 while(n!=0){ 10 if((n&1) == 1) count++; 11 n = n>>>1; 12 } 13 return count; 14 } 15 }
使用辗转相除,超时。遂移位相与。