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  • ajax请求

     
    
    post请求
    
    var url = this.server + "?action=dwm_canbeoperated&tablename=" + tableName;
    url = $yw.g.id.appendUrl(url);
    data = JSON.stringify(data);
    var postData = {"data": data};
    $.ajax({
      async: false,
      cache: false,
      type: 'POST',
      data: postData,
      url: url,
      success: function (data) {
      result = data;
      result.type = "undelete";
      }
    })
    
    get请求
    
    $.ajax({
      async: false,
      cache: false,
      type: 'GET',
      url: edpurl,
      uccess: function (data) {
      var rows = data.rows;
      result.dataoperatorid = rows[0];
      }
    });
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  • 原文地址:https://www.cnblogs.com/gym2017/p/7228185.html
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