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  • 914. X of a Kind in a Deck of Cards

    In a deck of cards, each card has an integer written on it.

    Return true if and only if you can choose X >= 2 such that it is possible to split the entire deck into 1 or more groups of cards, where:

    • Each group has exactly X cards.
    • All the cards in each group have the same integer

    Example 1:

    Input: [1,2,3,4,4,3,2,1]
    Output: true
    Explanation: Possible partition [1,1],[2,2],[3,3],[4,4]
    

    Example 2:

    Input: [1,1,1,2,2,2,3,3]
    Output: false
    Explanation: No possible partition.
    

    Example 3:

    Input: [1]
    Output: false
    Explanation: No possible partition.
    

    Example 4:

    Input: [1,1]
    Output: true
    Explanation: Possible partition [1,1]
    

    Example 5:

    Input: [1,1,2,2,2,2]
    Output: true
    Explanation: Possible partition [1,1],[2,2],[2,2]

    Note:

    1. 1 <= deck.length <= 10000
    2. 0 <= deck[i] < 10000

    Approach #1: Array + GCD. [Java]

    class Solution {
        public boolean hasGroupsSizeX(int[] deck) {
            int res = 0;
            Map<Integer, Integer> map = new HashMap<>();
            for (int d : deck) map.put(d, map.getOrDefault(d, 0) + 1);
            for (int m : map.values()) res = gcd(res, m);
            return res > 1;
        }
        public int gcd(int x, int y) {
            return y > 0 ? gcd(y, x % y) : x;
        }
    }
    

      

    Reference:

    https://leetcode.com/problems/x-of-a-kind-in-a-deck-of-cards/discuss/175845/C%2B%2BJavaPython-Greatest-Common-Divisor

    永远渴望,大智若愚(stay hungry, stay foolish)
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  • 原文地址:https://www.cnblogs.com/h-hkai/p/10692728.html
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