You have a list of points in the plane. Return the area of the largest triangle that can be formed by any 3 of the points.
Example: Input: points = [[0,0],[0,1],[1,0],[0,2],[2,0]] Output: 2 Explanation: The five points are show in the figure below. The red triangle is the largest.
Notes:
3 <= points.length <= 50
.- No points will be duplicated.
-50 <= points[i][j] <= 50
.- Answers within
10^-6
of the true value will be accepted as correct.
Approach #1: Math. [Java]
class Solution { public double largestTriangleArea(int[][] points) { double res = 0; for (int[] i : points) { for (int[] j : points) { for (int[] k : points) { res = Math.max(res, 0.5 * Math.abs(i[0] * j[1] + j[0] * k[1] + k[0] * i[1] - j[0] * i[1] - k[0] * j[1] - i[0] * k[1])); } } } return res; } }
Analysis:
Reference: