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  • 数据结构实验三不会的

    1、二叉树表达式求值

    基于二叉树的表达式求值
     

    描述

     

    输入一个表达式(表达式中的数均为小于10的正整数)利用二叉树来表示表达式,创建表达式树,然后利用二叉树的遍历操作求表达式的值



    输入

    多组数据。每组数据一行,为一个表达式,表达式以‘=’结尾。当输入只有一个“=”时,输入结束。

    输出

    每组数据输出一行,为表达式的值。

    输入样例 1 

    2*(2+5)=
    1+2=
    =

    输出样例 1

    14
    3

    #include<iostream>
    #include<stack>
    #include<string>
    #include<cstring>
    #include<queue>
    using namespace std;
    typedef struct Node* BinTree;
    typedef BinTree BT;
    string s;
    queue<char> num;
    queue<char> op;
    struct Node 
    {
        char Data;
        BT Left;
        BT Right;
        int ans;
    };
    
    int fact(char c)
    {
        if (c >= '0' && c <= '9') return 1;
        else return 2;
    }
    BT createNode(char c)
    {
        BT p = new Node;
        p->Data = c;
        p->Left = p->Right = NULL;
        if (fact(c) == 1)
            p->ans = c - '0';
        else
            p->ans = 0;
        return p;
    }
    BT createTree()
    {
        for (int i = 0; i < s.size() - 1; i++) 
        {
            if (fact(s[i]) == 1)
                num.push(s[i]);
            else 
                op.push(s[i]);
        }
        BT Head = NULL;
        int flag = 0;     //标记有括号时的情况 
        int sflag = 0;      //处理开始时为括号的情况 
        if (s[0] == '(') sflag = 1;
        while (!op.empty())//非空
        {
            char option;
            option = op.front();//取第一个运算符
            op.pop();
            if (option != '(' && option != ')') 
            {
                BT T = createNode(option);
                if (option == '+' || option == '-')
                {
                    if (flag == 0)
                    {
                        if (Head == NULL)
                        {
                            T->Left = createNode(num.front());
                            num.pop();
                            T->Right = createNode(num.front());
                            num.pop();//取两个数,作为两个孩子
                        }
                        else
                        {
                            T->Left = Head;
                            T->Right = createNode(num.front());
                            num.pop();
                        }
                        Head = T;
                    }
                    else 
                    {
                        if (Head == NULL)
                        {
                            T->Left = createNode(num.front());
                            num.pop();
                            T->Right = createNode(num.front());
                            num.pop();
                            Head = T;
                        }
                        else
                        {
                            T->Left = Head->Right;
                            Head->Right = T;
                            T->Right = createNode(num.front());
                            num.pop();
                        }
                    }
                }
                else 
                    if (option == '*' || option == '/')
                    {
                    if (flag == 0) 
                    {
                        if (Head == NULL)
                        {
                            T->Left = createNode(num.front());
                            num.pop();
                            T->Right = createNode(num.front());
                            num.pop();
                            Head = T;
                        }
                        else 
                        {
                            if (sflag == 1 || Head->Data == '*' || Head->Data == '/')
                            {
                                T->Left = Head;
                                Head = T;
                                T->Right = createNode(num.front());
                                num.pop();
                                sflag = 0;
                            }
                            else
                            {
                                T->Left = Head->Right;
                                Head->Right = T;
                                T->Right = createNode(num.front());
                                num.pop();
                            }
                        }
                    }
                    if (flag == 1) 
                    {
                        if (Head == NULL) 
                        {
                            T->Left = createNode(num.front());
                            num.pop();
                            T->Right = createNode(num.front());
                            num.pop();
                            Head = T;
                        }
                        else
                        {
                            T->Left = Head->Right;
                            Head->Right = T;
                            T->Right = createNode(num.front());
                            num.pop();
                        }
                    }
    
                }
            }
            else if (option == '(')
            {
                flag = 1;
                
            }
            else if (option == ')')
            {
                flag = 0;
            }
        }
        return Head;
    }
    
    void solve(BT L) 
    {
        if (L) 
        {
            solve(L->Left);
            solve(L->Right);
            char option = L->Data;
            if (option == '+') L->ans = L->Left->ans + L->Right->ans;
            if (option == '-') L->ans = L->Left->ans - L->Right->ans;
            if (option == '*') L->ans = L->Left->ans * L->Right->ans;
            if (option == '/') L->ans = L->Left->ans / L->Right->ans;
    
        }
    }
    
    int main() {
        while (cin >> s && s[0] != '=') 
        {
            BT H = createTree();
            solve(H);
            cout << H->ans << endl;
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/h694879357/p/11883331.html
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