C++实现字符串分割（类似于Python的split方法）

先学Python后学其他语言的后遗症就是Python中很多好用的方法在别的语言中都找不到

所以自己写一个吧

#include "stdafx.h"
#include <iostream>
#include <list>

void stringSplit(std::string msg, std::string part, std::list<std::string> &result)
{
    int msgLen = msg.length();
    int partLen = part.length();
    int offset = 0;
    std::string ele = "";
    std::cout << "msg length:" << msgLen << "part length:" << partLen << std::endl;
    while (offset < msgLen)
    {
        int stop = offset + partLen;
        std::string piece = msg.substr(offset, partLen);
        cout << "piece is " << piece << " offset is " << offset << " stop is " << stop << endl;
        if (piece == part)
        {
            result.push_back(ele);
            offset = offset + partLen;
            ele = "";
        }
        else
        {
            ele = ele + msg[offset];
            offset++;
        }
    }
    result.push_back(ele);
}

// limit 准备分割的次数， 如，2，代表函数发现两次分隔符，就会停止，返回长度为3的列表
void stringSplit(std::string msg, std::string part, std::list<std::string> &result, int limit)
{
    int msgLen = msg.length();
    int partLen = part.length();
    int offset = 0;
    std::string ele = "";
    std::cout << "msg length:" << msgLen << "part length:" << partLen << std::endl;
    int sign = 0;
    while (offset < msgLen)
    {
        int stop = offset + partLen;
        std::string piece = msg.substr(offset, partLen);
        cout << "piece is " << piece << " offset is " << offset << " stop is " << stop << endl;
        if (piece == part)
        {
            result.push_back(ele);
            offset = offset + partLen;
            ele = "";
            sign++;
            if (sign == limit){
                result.push_back(msg.substr(offset, msgLen - offset));
                return;
            }
        }
        else
        {
            ele = ele + msg[offset];
            offset++;
        }
    }
    result.push_back(ele);
}

对字符串进行一次遍历，每次切取与分隔符等长的一段，如果与分隔符一致，则将前一段字符串放入result，否则，当前位置往后移动一次