题目链接
贪心+优先队列,只要每次将数量前三大的半径拿出来就好了,用优先队列维护一下
#include<bits/stdc++.h>
#define rg register
#define file(x) freopen(x".in","r",stdin);freopen(x".out","w",stdout);
using namespace std;
int read(){
int x=0,f=1;
char c=getchar();
while(c<'0'||c>'9') f=(c=='-')?-1:1,c=getchar();
while(c>='0'&&c<='9') x=x*10+c-48,c=getchar();
return f*x;
}
struct hh{
int v,id;
bool operator < (hh a) const {
return v<a.v;
}
}a[100001];
struct node {
int x,y,z;
}c[100001];
int b[100001],d[100001];
priority_queue<hh> q;
int main(){
int n=read(),tot=1,cnt=0;
for(int i=1;i<=n;i++)
a[i].v=read(),a[i].id=i;
sort(a+1,a+1+n);
a[0].v=-2147483647;
for(int i=2;i<=n+1;i++){
if(a[i].v!=a[i-1].v){
hh now;
now.id=a[i-1].v,now.v=tot;
q.push(now),tot=1;
}
else
tot++;
}
hh now;
now=q.top();
int cc=0;
while(q.size()>=3){
hh now1,now2,now3;
now1=q.top(),q.pop();
now2=q.top(),q.pop();
now3=q.top(),q.pop();
now1.v--,now2.v--,now3.v--;
if(now1.v) q.push(now1),cc++;
if(now2.v) q.push(now2),cc++;
if(now3.v) q.push(now3),cc++;
c[++cnt].x=now1.id,c[cnt].y=now2.id,c[cnt].z=now3.id;
}
printf("%d
",cnt);
for(int i=1;i<=cnt;i++){
int l=min(c[i].x,min(c[i].y,c[i].z)),r=max(c[i].x,max(c[i].y,c[i].z));
printf("%d ",r);
if(c[i].x<r&&c[i].x>l)
printf("%d ",c[i].x);
if(c[i].y<r&&c[i].y>l)
printf("%d ",c[i].y);
if(c[i].z<r&&c[i].z>l)
printf("%d ",c[i].z);
printf("%d
",l);
}
return 0;
}