zoukankan      html  css  js  c++  java
  • [leetcode-733-Flood Fill]

    An image is represented by a 2-D array of integers, each integer representing the pixel value of the image (from 0 to 65535).

    Given a coordinate (sr, sc) representing the starting pixel (row and column) of the flood fill, and a pixel value newColor, "flood fill" the image.

    To perform a "flood fill", consider the starting pixel, plus any pixels connected 4-directionally to the starting pixel of the same color as the starting pixel, plus any pixels connected 4-directionally to those pixels (also with the same color as the starting pixel), and so on. Replace the color of all of the aforementioned pixels with the newColor.

    At the end, return the modified image.

    Example 1:

    Input: 
    image = [[1,1,1],[1,1,0],[1,0,1]]
    sr = 1, sc = 1, newColor = 2
    Output: [[2,2,2],[2,2,0],[2,0,1]]
    Explanation: 
    From the center of the image (with position (sr, sc) = (1, 1)), all pixels connected 
    by a path of the same color as the starting pixel are colored with the new color.
    Note the bottom corner is not colored 2, because it is not 4-directionally connected
    to the starting pixel.
    

    Note:

    • The length of image and image[0] will be in the range [1, 50].
    • The given starting pixel will satisfy 0 <= sr < image.length and 0 <= sc < image[0].length.
    • The value of each color in image[i][j] and newColor will be an integer in [0, 65535].

    思路:

    DFS即可,但是发现一个怪现象,就是在主函数里面必须加上如下判断,要不然不能ac,不知道为什么。。。

    if(image[sr][sc] != newColor)
    void fill(vector<vector<int>>& image,int m,int n,int r,int c,int color,int newcolor)
    {
        if(r < 0 || r >= m || c < 0 || c>= n || image[r][c] != color)return;
        image[r][c] = newcolor;
        fill(image,m,n,r+1,c,color,newcolor);
        fill(image,m,n,r-1,c,color,newcolor);
        fill(image,m,n,r,c+1,color,newcolor);
        fill(image,m,n,r,c-1,color,newcolor);
    }
    vector<vector<int>> floodFill(vector<vector<int>>& image, int sr, int sc, int newColor)
    {
        int m = image.size(),n = image[0].size();
    
        if(image[sr][sc] != newColor)fill(image,m,n,sr,sc,image[sr][sc],newColor);
        
        return image;        
    }
  • 相关阅读:
    python os.open()和open()
    巨坑:浏览器在短时间内对于同一个请求的处理,会先等待上一个请求完成后,再处理下一个请求,导致在测试异步时误导代码有问题。
    写在开始
    租房小记
    小聚随笔
    由游戏想。(补发)
    对于devOps的一些理解(补发)
    写在2020-01-30(补发)
    杂谈
    如何对抗无意识状态(补发)
  • 原文地址:https://www.cnblogs.com/hellowooorld/p/8066516.html
Copyright © 2011-2022 走看看