各个位数和，找最终和为个位数

Eddy's digital Roots

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2433    Accepted Submission(s): 1391

Problem Description

The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the process is repeated. This is continued as long as necessary to obtain a single digit. For example, consider the  positive integer 24. Adding the 2 and the 4 yields a value of 6. Since 6 is a  single digit, 6 is the digital root of 24. Now consider the positive integer 39.  Adding the 3 and the 9 yields 12. Since 12 is not a single digit, the process  must be repeated. Adding the 1 and the 2 yeilds 3, a single digit and also the  digital root of 39. The Eddy's easy problem is that : give you the n,want  you to find the n^n's digital Roots.

 

Input

The input file will contain a list of positive integers  n, one per line. The end of the input will be indicated by an integer value of  zero. Notice:For each integer in the input n(n<10000).

 

Output

Output n^n's digital root on a separate line of the  output.

 

Sample Input

2 4 0

 

Sample Output

4 4

#include<stdio.h>
int powmod (int a,int b,int n)
{ 
	if(b==0)return 1;
	int k=1; 
	while(b>=1)
	{  
		if(b%2!=0)k=a*k%n;
		a=((a%n)*(a%n))%n;
		b/=2; 
	}
	return k;
}
main()
{
	int n;
	while(scanf("%d",&n),n)
	{
		if(powmod(n,n,9)==0)
			printf("9\n");
		else
			printf("%d\n",powmod(n,n,9));	
	}
}