zoukankan      html  css  js  c++  java
  • 21次C++作业

      1 //第一题目
      2 class A                   //A为基类
      3 {public:
      4   void f1( );
      5   int i;
      6  protected:
      7   void f2();
      8   int j;
      9  private:
     10   int k;
     11 };
     12 /*f4里面是可以调用的
     13 C的对象不能直接调用f2()的成员函数里
     14 f2()也是类C的protected 函数在C++中派生类的成员函数是可以直接访问基类的保护成员和公有成员。
     15 */
     16 class B: public A            //B为A的公用派生类
     17 {public:
     18   void f3( );
     19  protected:
     20   int m;
     21  private:
     22   int n;
     23 };
     24 
     25 class C: public B              //C为B的公用派生类
     26 {public:
     27   void f4();
     28  private:
     29   int p;
     30 };
     31 
     32 int main()
     33 {A a1;                         //a1是基类A的对象
     34  B b1;                         //b1是派生类B的对象
     35  C c1;                         //c1是派生类C的对象
     36  return 0;
     37 }
     38 //(1)b1.i,b1.j可以,b1.k不可以
     39 //(2)可以
     40 //(3)i,j可以,k不可以
     41 //(4)i,j,m,p可以,k,n,p不可以
     42 //(5)可以
     43 //(6)可以
     44 //第二题目
     45 #include <iostream>
     46 using namespace std;
     47 class A
     48 {public:
     49   void f1( );
     50  protected:
     51   void f2();
     52  private:
     53   int i;
     54 };
     55 
     56 class B: public A
     57 {public:
     58   void f3( );
     59   int k;
     60  private:
     61   int m;
     62 };
     63 
     64 class C: protected B
     65 {public:
     66   void f4();
     67  protected:
     68   int n;
     69  private:
     70   int p;
     71 };
     72 
     73 class D: private C
     74 {public:
     75   void f5();
     76  protected:
     77   int q;
     78  private:
     79   int r;
     80 };
     81 
     82 int main()
     83 {A a1;
     84  B b1;
     85  C c1;
     86  D d1;
     87  return 0;
     88 }
     89 //第三题目
     90 #include <iostream>
     91 using namespace std;
     92 class A
     93  {
     94   public:
     95    A(){a=0;b=0;}
     96    A(int i){a=i;b=0;}
     97    A(int i,int j){a=i;b=j;}
     98    void display(){cout<<"a="<<a<<" b="<<b;}
     99   private:
    100    int a;
    101    int b;
    102  };
    103 
    104 class B  : public A
    105  {
    106   public:
    107    B(){c=0;}
    108    B(int i):A(i){c=0;}
    109    B(int i,int j):A(i,j){c=0;}
    110    B(int i,int j,int k):A(i,j){c=k;}
    111    void display1()
    112     {display();
    113      cout<<" c="<<c<<endl;
    114     }
    115    private:
    116     int c;
    117 };
    118 
    119 int main()
    120 {   B b1;
    121     B b2(1);
    122     B b3(1,3);
    123     B b4(1,3,5);
    124     b1.display1();//a=0,b=0,c=0
    125     b2.display1();//a=1,b=0,c=0
    126     b3.display1();//a=1,b=3,c=0
    127     b4.display1();//a=1,b=3,c=5
    128     return 0;
    129 }
    130 //第四题目
    131 #include <iostream>
    132 using namespace std;
    133 class A
    134  {
    135   public:
    136    A(){cout<<"constructing A "<<endl;}
    137    ~A(){cout<<"destructing A "<<endl;}
    138  };
    139 
    140 class B  : public A
    141  {
    142   public:
    143    B(){cout<<"constructing B "<<endl;}
    144    ~B(){cout<<"destructing B "<<endl;}
    145 };
    146 
    147 class C  : public B
    148  {
    149   public:
    150    C(){cout<<"constructing C "<<endl;}
    151    ~C(){cout<<"destructing C "<<endl;}
    152 };
    153 int main()
    154 { C c1;
    155   return 0;
    156 }
    157 //a(),b(),c(),~c(),~b(),~a()构造从基类开始,析构顺序相反
    158 //第五题目
    159 #include<string>
    160 #include <iostream>
    161 using namespace std;
    162 class Teacher
    163  {public:
    164    Teacher(string nam,int a,char s,string tit,string ad,string t);
    165    void display();
    166   protected:
    167     string name;
    168     int age;
    169     char sex;
    170     string title;
    171     string addr;
    172     string tel;
    173 };
    174 
    175 Teacher::Teacher(string nam,int a,char s,string tit,string ad,string t):
    176      name(nam),age(a),sex(s),title(tit),addr(ad),tel(t){ }
    177 void Teacher::display()
    178      {cout<<"name:"<<name<<endl;
    179       cout<<"age"<<age<<endl;
    180       cout<<"sex:"<<sex<<endl;
    181       cout<<"title:"<<title<<endl;
    182       cout<<"address:"<<addr<<endl;
    183       cout<<"tel:"<<tel<<endl;
    184       }
    185 
    186 class Cadre
    187  {public:
    188    Cadre(string nam,int a,char s,string p,string ad,string t);
    189    void display();
    190   protected:
    191    string name;
    192    int age;
    193    char sex;
    194    string post;
    195    string addr;
    196    string tel;
    197  };
    198  
    199 Cadre::Cadre(string nam,int a,char s,string p,string ad,string t):
    200      name(nam),age(a),sex(s),post(p),addr(ad),tel(t){}
    201      
    202 void Cadre::display()
    203     {cout<<"name:"<<name<<endl;
    204      cout<<"age:"<<age<<endl;
    205      cout<<"sex:"<<sex<<endl;
    206      cout<<"post:"<<post<<endl;
    207      cout<<"address:"<<addr<<endl;
    208      cout<<"tel:"<<tel<<endl;
    209     }
    210 
    211 class Teacher_Cadre:public Teacher,public Cadre
    212  {public:
    213    Teacher_Cadre(string nam,int a,char s,string tit,string p,string ad,string t,float w);
    214    void show( );
    215   private:
    216     float wage;
    217  };
    218  
    219 Teacher_Cadre::Teacher_Cadre(string nam,int a,char s,string t,string p,string ad,string tel,float w):
    220   Teacher(nam,a,s,t,ad,tel),Cadre(nam,a,s,p,ad,tel),wage(w) {}
    221 void Teacher_Cadre::show( )
    222     {Teacher::display();//调用teacher的display函数输出
    223      cout<<"post:"<<Cadre::post<<endl;
    224      cout<<"wages:"<<wage<<endl;
    225      }
    226 
    227 int main( )
    228  {Teacher_Cadre te_ca("Wang-li",50,'f',"prof.","president","135 Beijing Road,Shanghai","(021)61234567",1534.5);
    229   te_ca.show( );
    230   return 0;
    231 }
  • 相关阅读:
    Install and Configure OSSEC on Debian 7&8
    手动替换WORDPRESS的GOOGLE字体等加速【非插件】
    LDAP常用命令解析
    Install guide for OpenLDAP and GOsa 2 on Ubuntu & Debian
    Linux 转发 email Redirect local emails to a remote email account
    Ubuntu,忘记了root密码,怎么重置?
    LDAP 原理图解
    CAS实现SSO单点登录原理
    cacti 安装与 与不能显示图像故障解决方案
    LDAP概念和原理
  • 原文地址:https://www.cnblogs.com/herizai/p/3140527.html
Copyright © 2011-2022 走看看