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java中的List记录是否完全匹配方法

今天要说的是给List分组，然后用Map来封装，可能你看了以后还是有一些模糊。

先看一下项目结构图：

User类是一个VO类，主要逻辑还是在MapTestBak上面。

运行效果：

原理图：

1.在starsList中有两组人，共三人

2.在dolList中有一组人，共两人

3.经过marched操作，最后匹配到一组人到result中。即第一组人。

原理很简单。

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源码部分：

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/mapTest/src/com/b510/map/MapTestBak.java

  1 /**
  2  * 
  3  */
  4 package com.b510.map;
  5 
  6 import java.util.ArrayList;
  7 import java.util.HashMap;
  8 import java.util.List;
  9 import java.util.Map;
 10 
 11 /**
 12  * @author Hongten
 13  * @created Apr 28, 2014
 14  */
 15 public class MapTestBak {
 16 
 17     public static void main(String[] args) {
 18         mapTest();
 19     }
 20 
 21     /**
 22      * 
 23      */
 24     private static void mapTest() {
 25         // starsList
 26         List<User> starsList = getStarsList();
 27 
 28         // dolList
 29         List<User> dolList = getDolList();
 30 
 31         Map<String, List<User>> map = groupingHandler(starsList);
 32         // test
 33         groupingHandlerTest(map);
 34 
 35         System.out.println("======= group finished =======");
 36         List<Map<String, List<User>>> compareResultList = compare(dolList, map);
 37         if(null != compareResultList){
 38             System.out.println(compareResultList.size());
 39         }
 40     }
 41 
 42     /**
 43      * @param dolList
 44      * @param map
 45      */
 46     private static List<Map<String, List<User>>> compare(List<User> dolList, Map<String, List<User>> map) {
 47         List<Map<String, List<User>>>  tempList = new ArrayList<Map<String, List<User>>>();
 48         if (null != map) {
 49             for (String key : map.keySet()) {
 50                 List<User> u = map.get(key);
 51                 List comList = new ArrayList();
 52                 boolean comFlag = true;
 53                 for (User us : u) {
 54                     List comList1 = new ArrayList();
 55                     for (User ul : dolList) {
 56                         if (us.getGroupNO() == ul.getGroupNO() && us.getName().trim().equals(ul.getName().trim())) {
 57                             comList1.add(1);
 58                         } else {
 59                             comList1.add(0);
 60                         }
 61                     }
 62                     if (comList1.contains(1)) {
 63                         // name has existed.
 64                         comList.add(1);
 65                     } else {
 66                         comList.add(0);
 67                     }
 68                 }
 69                 if (comList.contains(0)) {
 70                     comFlag = false;
 71                 }
 72                 // print out the match result in the console.
 73                 printMatchResult(tempList, key, u, comFlag);
 74             }
 75         }else{
 76             System.out.println("map is null!");
 77         }
 78         return tempList;
 79     }
 80 
 81     /**
 82      * @param tempList
 83      * @param key
 84      * @param u
 85      * @param comFlag
 86      */
 87     private static void printMatchResult(List<Map<String, List<User>>> tempList, String key, List<User> u, boolean comFlag) {
 88         if (comFlag) {
 89             // do something
 90             System.out.println("group : " + key + " compared!
 Detail:");
 91             System.out.println("================");
 92             for (User ut : u) {
 93                 System.out.println(ut.getGroupNO() + ", " + ut.getName());
 94             }
 95             System.out.println("================");
 96             Map<String, List<User>> tempMap = new HashMap<String, List<User>>();
 97             tempMap.put(key, u);
 98             tempList.add(tempMap);
 99         } else {
100             System.out.println("group : " + key + " NOT compared!");
101         }
102     }
103 
104     /**
105      * @param map
106      */
107     private static void groupingHandlerTest(Map<String, List<User>> map) {
108         if (null != map) {
109             for (String key : map.keySet()) {
110                 List<User> u = map.get(key);
111                 for (User u1 : u) {
112                     System.out.println(u1.getGroupNO() + ", " + u1.getName());
113                 }
114             }
115         }
116     }
117 
118     /**
119      * @param starsList
120      * @param map
121      */
122     private static Map<String, List<User>> groupingHandler(List<User> starsList) {
123         Map<String, List<User>> map = new HashMap<String, List<User>>();
124         for (User stars_user : starsList) {
125             String no = String.valueOf(stars_user.getGroupNO());
126             if (map.isEmpty()) {
127                 List<User> l = new ArrayList<User>();
128                 l.add(stars_user);
129                 map.put(no, l);
130             } else {
131                 List<User> user_map = map.get(no);
132                 if (null == user_map || "".equals(user_map)) {
133                     List<User> l = new ArrayList<User>();
134                     l.add(stars_user);
135                     map.put(no, l);
136                 } else {
137                     List<User> l = map.get(no);
138                     l.add(stars_user);
139                     map.put(no, l);
140                 }
141             }
142         }
143         return map;
144     }
145 
146     /**
147      * @param dolList
148      */
149     private static List<User> getDolList() {
150         List<User> dolList = new ArrayList<User>();
151         User user_B1_dol = new User(1, "MRS KON");
152         User user_A_dol = new User(1, "KON SUE");
153         dolList.add(user_B1_dol);
154         dolList.add(user_A_dol);
155         return dolList;
156     }
157 
158     /**
159      * @param starsList
160      */
161     private static List<User> getStarsList() {
162         List<User> starsList = new ArrayList<User>();
163         User user_B1 = new User(1, "MRS KON");
164         User user_A = new User(1, "KON SUE");
165         User user_B2 = new User(2, "MRS KON");
166         User user_C = new User(2, "LON MEI");
167         starsList.add(user_B1);
168         starsList.add(user_A);
169         starsList.add(user_B2);
170         starsList.add(user_C);
171         return starsList;
172     }
173 }

/mapTest/src/com/b510/map/User.java

 1 /**
 2  * 
 3  */
 4 package com.b510.map;
 5 
 6 /**
 7  * @author Hongten
 8  * @created Apr 28, 2014
 9  */
10 public class User {
11 
12     private int groupNO;
13     private String name;
14 
15     public int getGroupNO() {
16         return groupNO;
17     }
18 
19     public User(int groupNO, String name) {
20         this.groupNO = groupNO;
21         this.name = name;
22     }
23 
24     public void setGroupNO(int groupNO) {
25         this.groupNO = groupNO;
26     }
27 
28     public String getName() {
29         return name;
30     }
31 
32     public void setName(String name) {
33         this.name = name;
34     }
35 
36 }

我想要记录一下的是方法：compare(List<User> dolList, Map<String, List<User>> map)

 1 private static List<Map<String, List<User>>> compare(List<User> dolList, Map<String, List<User>> map) {
 2         List<Map<String, List<User>>>  tempList = new ArrayList<Map<String, List<User>>>();
 3         if (null != map) {
 4             for (String key : map.keySet()) {
 5                 List<User> u = map.get(key);
 6                 List comList = new ArrayList();
 7                 boolean comFlag = true;
 8                 for (User us : u) {
 9                     List comList1 = new ArrayList();
10                     for (User ul : dolList) {
11                         if (us.getGroupNO() == ul.getGroupNO() && us.getName().trim().equals(ul.getName().trim())) {
12                             comList1.add(1);
13                         } else {
14                             comList1.add(0);
15                         }
16                     }
17                     if (comList1.contains(1)) {
18                         // name has existed.
19                         comList.add(1);
20                     } else {
21                         comList.add(0);
22                     }
23                 }
24                 if (comList.contains(0)) {
25                     comFlag = false;
26                 }
27                 // print out the match result in the console.
28                 printMatchResult(tempList, key, u, comFlag);
29             }
30         }else{
31             System.out.println("map is null!");
32         }
33         return tempList;
34     }

在这个方法中，这里使用了两个List（即：comList, comList1）来记录是否完全匹配。

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多读一些书，英语很重要。