1.编写一个简单程序,要求数组长度为5,静态赋值10,20,30,40,50,在控制台输出该数组的值。
import java.util.*; public class jkk { public static void main(String[] args) { int[] arr = new int[] { 10, 20, 30, 40, 50 }; for (int i = 0; i < arr.length; i++) { System.out.print(arr[i] + " "); } } }
2.编写一个简单程序,要求数组长度为5,动态赋值10,20,30,40,50,在控制台输出该数组的值。
import java.util.*; public class jkk { public static void main(String[] args) { int[] a = new int[5]; a[0] = 10; a[1] = 20; a[2] = 30; a[3] = 40; a[4] = 50; for (int i = 0; i < a.length; i++) { System.out.println(a[i]); } } }
3.编写一个简单程序,定义整型数组,里面的元素是{23,45,22,33,56},求数组元素的和、平均值
import java.util.*; public class jkk { public static void main(String[] args) { int a[] = { 23, 45, 22, 33, 56 }; double sum = 0; for (int i = 0; i < a.length; i++) { sum += a[i]; } System.out.print("和" + sum + "平均值" + sum / 5); } }
4.在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标。
import java.util.*; public class jkk { public static void main(String[] args) { int a[] = { 18, 25, 7, 36, 13, 2, 89, 63 }; int max = a[0]; int index = 0; for (int i = 1; i < a.length; i++) { if (max < a[i]) { max = a[i]; index = i; } } System.out.print("最大数是" + max + "下标是" + index); } }
5. 将一个数组中的元素逆序存放(知识点:数组遍历、数组元素访问)
import java.util.*; public class jkk { public static void main(String[] args) { int[] a = new int[] { 1, 2, 3, 4, 5 }; int b; for (int i = 0; i < a.length / 2; i++) { b = a[i]; a[i] = a[a.length - 1 - i]; a[a.length - 1 - i] = b; } for (int i = 0; i < a.length; i++) { System.out.print(a[i] + ", "); } } }