sqlite 获取当天当周当月等数据

----昨天
select * from 表 where Time>=datetime('now','start of day','-1 day') and Time<datetime('now','start of day','+0 day')

----当天
select * from 表 where Time>=datetime('now','start of day','+0 day') and Time<datetime('now','start of day','+1 day')

----当周
select  * from 表 where Time>=datetime('now','start of day','-7 day','weekday 1') AND Time<datetime('now','start of day','+0 day','weekday 1')

----当月
select * from 表 where Time>=datetime('now','start of month','+0 month','-0 day') AND Time < datetime('now','start of month','+1 month','0 day')

----上月
select * from 表 where Time>=datetime('now','start of month','-1 month','-0 day') AND Time <datetime('now','start of month','+0 month','-1 day')

 上面的“当周”和“当月”的获取方法，知识取最近7（30）天，并非本周（本月）。

下面是经过测试可以用的方法：

--本月
select *
from UserConsume
where rowTime between datetime('now','start of month','+1 second') and 
datetime('now','start of month','+1 month','-1 second') 


--本周
select *
from UserConsume
where rowTime between datetime(date(datetime('now',strftime('-%w day','now'))),'+1 second') 
and datetime(date(datetime('now',(6 - strftime('%w day','now'))||' day','1 day')),'-1 second') 

----上面本周的计算再次出错，再次修正：

--start 
select datetime("now","start of day","-6 day","weekday 1")

--end
select datetime(datetime("now","start of day","weekday 0"),"start of day","+1 day")