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  • Min Stack

    Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.

    • push(x) -- Push element x onto stack.
    • pop() -- Removes the element on top of the stack.
    • top() -- Get the top element.
    • getMin() -- Retrieve the minimum element in the stack.

    Example:

    MinStack minStack = new MinStack();
    minStack.push(-2);
    minStack.push(0);
    minStack.push(-3);
    minStack.getMin();   --> Returns -3.
    minStack.pop();
    minStack.top();      --> Returns 0.
    minStack.getMin();   --> Returns -2.


    class MinStack {
        
        Stack<Integer> element = new Stack<Integer>();
        Stack<Integer> minStack = new Stack<Integer>();
        public void push(int x) 
        {
            // element.add(x);
            // if (minStack.isEmpty() || x <= minStack.peek()) 
            // {
            //       minStack.add(x);
            // }
            if(minStack.isEmpty())
            {
                minStack.add(x);
                element.add(x);
            }
            else
            {
                int a = minStack.peek();
                minStack.add(Math.min(x,a));
                element.add(x);
            }
        }
    
        public void pop() 
        {
            if(element.isEmpty()) return;
            // if (element.peek().equals(minStack.peek())) 
            // {
            //      minStack.pop();
            //  }
            minStack.pop();
            element.pop();
        }
    
        public int top() 
        {
            return element.peek();
            
        }
    
        public int getMin() 
        {
            return minStack.peek();
            
        }
    }

    reference: http://algorithms.tutorialhorizon.com/track-the-maximum-element-in-a-stack/

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  • 原文地址:https://www.cnblogs.com/hygeia/p/4815099.html
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