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  • Contest 153

    2019-09-14 23:16:25

    总体感受:节奏尚可,难度尚可。然而还是卡在了最后一题,完全没有想到使用dp。

    注意点

    1)Contest的最后一题往往是DP,Graph,这个敏感度需要提高;

    2)DP的题目还是远远不够熟练。

    • 801. Minimum Swaps To Make Sequences Increasing

    问题描述:

    问题求解:

    keep[i] : 保留i位置的数字,使得[0, i]两个数组递增的最小交换次数。

    swap[i] : 交换i位置的数字,使得[0, i]两个数组递增的最小交换次数。

        public int minSwap(int[] A, int[] B) {
            int n = A.length;
            int[] keep = new int[n];
            int[] swap = new int[n];
            Arrays.fill(keep, n);
            Arrays.fill(swap, n);
            keep[0] = 0;
            swap[0] = 1;
            for (int i = 1; i < n; i++) {
                if (A[i] > A[i - 1] && B[i] > B[i - 1]) keep[i] = Math.min(keep[i], keep[i - 1]);
                if (A[i] > B[i - 1] && B[i] > A[i - 1]) keep[i] = Math.min(keep[i], swap[i - 1]);
                if (B[i] > A[i - 1] && A[i] > B[i - 1]) swap[i] = Math.min(swap[i], keep[i - 1] + 1);
                if (B[i] > B[i - 1] && A[i] > A[i - 1]) swap[i] = Math.min(swap[i], swap[i - 1] + 1);
            }
            return Math.min(keep[n - 1], swap[n - 1]);
        }
    

      

    • 1187. Make Array Strictly Increasing

    问题描述:

    问题求解:

        public int makeArrayIncreasing(int[] arr1, int[] arr2) {
            int n = arr1.length;
            int[] keep = new int[n];
            
            Set<Integer> set = new TreeSet<>();
            for (int num : arr2) set.add(num);
            int m = set.size();
            int[] sorted = new int[m];
            int idx = 0;
            for (int num : set) sorted[idx++] = num;
            int[] swap = new int[m];
            
            Arrays.fill(keep, n + 1);
            keep[0] = 0;
            for (int i = 0; i < m; i++) swap[i] = 1;
            for (int i = 1; i < n; i++) {
                if (arr1[i] > arr1[i - 1]) keep[i] = keep[i - 1];
                int cur_min = n;
                for (int j = 0; j < m; j++) {
                    int cur_swap = n + 1;
                    if (arr1[i] > sorted[j]) keep[i] = Math.min(keep[i], swap[j]);
                    int temp = cur_min;
                    cur_min = Math.min(cur_min, swap[j]);
                    if (sorted[j] > arr1[i - 1]) cur_swap = Math.min(cur_swap, keep[i - 1] + 1);
                    cur_swap = Math.min(cur_swap, temp + 1);
                    swap[j] = cur_swap;
                }
            }
            int res = Math.min(n + 1, keep[n - 1]);
            for (int i = 0; i < m; i++) res = Math.min(res, swap[i]);
            return res > n ? -1 : res;
        }
    

      

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  • 原文地址:https://www.cnblogs.com/hyserendipity/p/11520727.html
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