zoukankan      html  css  js  c++  java
  • FZU 2028 时空门问题

    题目链接:时空门问题

    简单bfs,每个格子移动的方式除了上下左右,还有时空门,开始想着用邻接表保存每个点能通过时空门到达的点就ok了。很快的敲出来,很快的WA了。长久的dbug并没有发现error。然后换成vector存储,AC,再换成邻接表WA......感觉明明一模一样的好吗...讨厌bug!【怒】

    =============================第二天晚上,神奇的大腿发现,我的head数组开成了maxn,然而实际上是maxn*maxn...沃日...最多有maxn*maxn个点啊....................早知道重构好了....

    邻接表代码:AC

    #include <stdio.h>
    #include <string.h>
    #include <iostream>
    #define maxn 600
    using namespace std;
    
    char mp[maxn][maxn];
    int n, m;
    
    struct Node {
        int u, v, nxt;
    }edge[maxn*maxn];
    
    struct Point {
        int x, y;
        int step;
    }point[maxn*maxn], st, ed, temp;
    
    int head[maxn*maxn];
    int tot;
    
    void addEdge(int u, int v) {
        edge[tot].u = u;
        edge[tot].v = v;
        edge[tot].nxt = head[u];
        head[u] = tot++;
    }
    
    Point que[maxn*maxn];
    int top, tail;
    bool vis[maxn][maxn];
    
    int dir[4][2] = {1, 0, -1, 0, 0, 1, 0, -1};
    
    bool check(Point a) {
        if (a.x >= 0 && a.x < n && a.y >= 0 && a.y < m && mp[a.x][a.y] != '#' && !vis[a.x][a.y])
            return true;
        return false;
    }
    
    void bfs(Point st) {
        top = 0, tail = -1;
        vis[st.x][st.y] = 1;
        que[++tail] = st;
    
    
        while(top <= tail) {
            Point now = que[top++];
            if (now.x == ed.x && now.y == ed.y) {
                    ed.step = now.step;
                    return;
            }
            for (int i=0; i<4; ++i) {
                Point nxt;
                nxt.x = now.x + dir[i][0];
                nxt.y = now.y + dir[i][1];
                if (check(nxt)) {
                    vis[nxt.x][nxt.y] = 1;
                    nxt.step = now.step + 1;
                    que[++tail] = nxt;
                }
            }
    
            int stp = now.x * m + now.y;
            for (int i=head[stp]; i!=-1; i=edge[i].nxt) {
                int edp = edge[i].v;
                Point nxt;
                nxt.x = edp / m, nxt.y = edp % m;
                if (check(nxt)) {
                    vis[nxt.x][nxt.y] = 1;
                    nxt.step = now.step + 1;
                    que[++tail] = nxt;
                }
            }
        }
        return;
    }
    
    int main() {
        while(~scanf("%d%d", &n, &m)) {
            tot = 0;
            memset(head, -1, sizeof(head));
            memset(vis, 0, sizeof(vis));
            getchar();
            for (int i=0; i<n; ++i) {
                for (int j=0; j<m; ++j) {
                    scanf("%c", &mp[i][j]);
                    if (mp[i][j] == 's') {
                        st.x = i, st.y = j;
                        st.step = 0;
                    }
                    else if (mp[i][j] == 't') {
                        ed.x = i, ed.y = j;
                    }
                }
                if (i != n-1) scanf("
    ");
            }
    
            for (int i=0; i<n*m; ++i) {
                int t;
                scanf("%d", &t);
                for (int j=0; j<t; ++j) {
                    int edx, edy;
                    scanf("%d%d", &edx, &edy);
                    edx -= 1, edy -= 1;
                    addEdge(i, edx*m+edy);
                }
            }
    
    //        for (int i=0; i<n*m; ++i) {
    //            cout << head[i] << "....
    ";
    //            for (int j=head[i]; j!=-1; j=edge[j].nxt) {
    //                cout << edge[j].u << " " << edge[j].v << endl;
    //            }
    //            cout << "++++++++++++++
    ";
    //        }
    
            bfs(st);
            printf("%d
    ", ed.step);
        }
        return 0;
    }
    
    
    /*
    2 3
    s.#
    ..t
    1
    2 2
    0
    0
    0
    1
    1 2
    0
    
    */
    

    vector代码:AC

    #include <stdio.h>
    #include <string.h>
    #include <iostream>
    #define maxn 600
    #include <vector>
    using namespace std;
    
    char mp[maxn][maxn];
    int n, m;
    
    vector<int>num[maxn*maxn];
    
    struct Point {
        int x, y;
        int step;
    }point[maxn*maxn], st, ed, temp;
    
    int tot;
    Point que[maxn*maxn];
    int top, tail;
    bool vis[maxn][maxn];
    
    int dir[4][2] = {1, 0, -1, 0, 0, 1, 0, -1};
    
    bool check(Point a) {
        if (a.x >= 0 && a.x < n && a.y >= 0 && a.y < m && mp[a.x][a.y] != '#' && !vis[a.x][a.y])
            return true;
        return false;
    }
    
    void bfs(Point st) {
        top = 0, tail = -1;
        vis[st.x][st.y] = 1;
        que[++tail] = st;
    
    
        while(top <= tail) {
            Point now = que[top++];
            if (now.x == ed.x && now.y == ed.y) {
                    ed.step = now.step;
                    return;
            }
            for (int i=0; i<4; ++i) {
                Point nxt;
                nxt.x = now.x + dir[i][0];
                nxt.y = now.y + dir[i][1];
                if (check(nxt)) {
                    vis[nxt.x][nxt.y] = 1;
                    nxt.step = now.step + 1;
                    que[++tail] = nxt;
                }
            }
    
            int stp = now.x * m + now.y;
            for (int i=0; i<num[stp].size(); ++i) {
                int edp = num[stp][i];
                Point nxt;
                nxt.x = edp / m, nxt.y = edp % m;
                if (check(nxt)) {
                    vis[nxt.x][nxt.y] = 1;
                    nxt.step = now.step + 1;
                    que[++tail] = nxt;
                }
            }
        }
        return;
    }
    
    int main() {
        while(~scanf("%d%d", &n, &m)) {
            tot = 0;
            memset(vis, 0, sizeof(vis));
            getchar();
            for (int i=0; i<n; ++i) {
                for (int j=0; j<m; ++j) {
                    scanf("%c", &mp[i][j]);
                    if (mp[i][j] == 's') {
                        st.x = i, st.y = j;
                        st.step = 0;
                    }
                    else if (mp[i][j] == 't') {
                        ed.x = i, ed.y = j;
                    }
                    num[i*m+j].clear();
                }
                if (i != n-1) scanf("
    ");
            }
    
            for (int i=0; i<n*m; ++i) {
                int t;
                scanf("%d", &t);
                for (int j=0; j<t; ++j) {
                    int edx, edy;
                    scanf("%d%d", &edx, &edy);
                    edx -= 1, edy -= 1;
                    num[i].push_back(edx*m+edy);
                }
            }
    
            bfs(st);
            printf("%d
    ", ed.step);
        }
        return 0;
    }
    
    
    /*
    2 3
    s.#
    ..t
    1
    2 2
    0
    0
    0
    1
    1 2
    0
    
    */
    

      

  • 相关阅读:
    缩减apk大小
    android 的安全问题
    android listview 优化
    Python正则表达式指南
    程序员必须知道的几个国外IT网站
    去掉配置项,开发自信的软件
    去掉配置项,开发自信的软件
    Linux防火墙设置
    Linux防火墙设置
    linux下如何使用sftp命令进行文件上传和下载
  • 原文地址:https://www.cnblogs.com/icode-girl/p/5371059.html
Copyright © 2011-2022 走看看