[LeetCode] Construct the Rectangle

For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.

2. The width W should not be larger than the length L, which means L >= W.

3. The difference between length L and width W should be as small as possible.

You need to output the length L and the width W of the web page you designed in sequence.

Example:

Input: 4
Output: [2, 2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. 
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

Note:

1. The given area won't exceed 10,000,000 and is a positive integer
2. The web page's width and length you designed must be positive integers.

题目要求找出组成矩阵的长和宽，要求长宽的差值尽可能小，并且长>宽。也就是说组成的矩阵尽可能像正方形。所以先对面积sqrt，找出最大的宽度，sqrt出来的值必须是宽度而不是长度，是因为sqrt出来的数是下取整。之后在计算长度。

class Solution {
public:
    vector<int> constructRectangle(int area) {
        int l = 1, w = 1;
        for (w = sqrt(area); w != 0; w--) 
            if (area % w == 0) {
                l = area / w;
                break;
            }
        return {l, w};
    }
};
// 3 ms