Question
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Solution
Classic DP problem. When we climb n steps, we have two choices for last step, either one step or two steps. To save space, we can further improve the solution using O(1) space.
1 public class Solution { 2 public int climbStairs(int n) { 3 if (n < 1) 4 return 0; 5 int[] dp = new int[3]; 6 dp[0] = 1; 7 dp[1] = 1; 8 for (int i = 2; i <= n; i++) { 9 dp[2] = dp[0] + dp[1]; 10 dp[0] = dp[1]; 11 dp[1] = dp[2]; 12 } 13 return dp[1]; 14 } 15 }