###思路:将重复的字符放入到list中,并进行计数统计
###实现:伪代码、函数、类实现
###伪代码:
string=s #给定的字符串
list=[] #放入重复的字符
dict={} #重复的字符进行统计
#判断字符串是否为空,逻辑实现
if str !=None:
for i in s:
if list !=None:
if i in list:
if i in dict.keys():
dict[i]+=1
else:
dict[i]=1
else:
list.append(i)
else:
list.append(i)
else:
print('输入的字符串为空!')
###python函数实现:
def judge_str(str):
str_list=[]
str_repet={}
if str !=None:
for i in str:
if not list is None:
if i in str_list:
if i in str_repet.keys():
str_repet[i]+=1
else:
str_repet[i]=1
else:
str_list.append(i)
else:
str_list.append(i)
print('该字符串中有%s个字符有重复'%len(str_repet.keys()))
for key,value in str_repet.items():
print('重复的字符为【%s】,共重复了%s次'%(key,value))
else:
print('输入的字符串是空!')
###python类的实现:
from functools import wraps
import time
def decorator(func):
@wraps(func)
def wrappres(*args,**kwargs):
start=time.time()
func(*args,**kwargs)
end=time.time()
usetime=end-start
print('查找共花费{:.2f}秒'.format(usetime))
return wrappres
class JudgeStr:
def __init__(self,string):
self.str_tuple=()
self.str_repet={}
self.string=string
self.str=self._filter_handler()
def _judge_handler(self):
for i in self.str:
if self.str_list !=None:
if i in self.str_list:
if i in self.str_repet.keys():
self.str_repet[i]+=1
else:
self.str_repet[i]=1
else:
self.str_list.append(i)
else:
self.str_list.append(i)
def _filter_handler(self):
if self.string !=None:
if type(self.string) ==str:
return self.string
else:
raise ValueError('请传入字符串参数')
else:
raise TypeError('参数为空')
@decorator
def result_handler(self):
self._judge_handler()
print('该字符串中有%s个字符有重复'%len(self.str_repet.keys()))
for key,value in self.str_repet.items():
print('重复的字符为【%s】,共重复了%s次'%(key,value))