react 实现点击跳转到拨号界面

import React, { Component } from 'react';

import {

    View,

    Text,

    Image,

    StyleSheet,

    TouchableOpacity,

    NativeModules,

    Platform,

    StatusBar,

    ScrollView,

    Alert ,

    Linking

} from "react-native";

import { Toast } from "../../components/base/Toast";

class GrabSheetVc extends Component {

    constructor(props) {

        super(props);

        this.state = {  }

        this.phone = 18888888888

    }

 render() {

        return (

　　

<View style={styles.v4}>

                            <TouchableOpacity style={{ borderRadius: 27, overflow: 'hidden', marginTop: 13 }} onPress={this.callMerchant}>

                                <Image

                                    source={require('../../../resource/order/telephone.png')}

                                    style={{  Utils.fontRem * 54, height: Utils.fontRem * 54 }}

                                    resizeMode='contain'

                                />

                            </TouchableOpacity>

                            <Text style={{ fontSize: 14, color: '#333', marginTop: 9.5 }}>联系雇主</Text>

</View>

)}

}

 /**

   *  拨打电话

   * @param {string} phone 版本号

   * @example

   * call('18888888888')

   */

  call = phone => {

    const url = `tel:${phone}`;

    Linking.canOpenURL(url)

      .then(supported => {

        if (!supported) {

          return Alert.alert('提示', `您的设备不支持该功能，请手动拨打 ${phone}`, [

            { text: '确定' }

          ]);

        }

        return Linking.openURL(url);

      })

      .catch(err => Toast.show(`出错了：${err}`, 1.5));

  };

  callMerchant = (phone) => {

    this.call(this.phone);

  };