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  • HDU 2295

    二分答案+重复覆盖。注意返回的条件哦,不能光套模板。

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    using namespace std;
    
    const int maxn=3600;
    const int maxc=55;
    const int maxr=55;
    const int inf=0x3f3f3f3f;
    const double rinf=1e10;
    int L[maxn], R[maxn], D[maxn], U[maxn], C[maxn];
    int S[maxc], H[maxr], size;
    int N,M,K;
    struct City{
    	double x,y;
    }cities[maxr];
    struct Radar{
    	double x,y;
    }radar[maxc];
    double map[55][55];
    ///²»ÐèÒªSÓò
    void Link(int r, int c)
    {
        S[c]++; C[size]=c;
        U[size]=U[c]; D[U[c]]=size;
        D[size]=c; U[c]=size;
        if(H[r]==-1) H[r]=L[size]=R[size]=size;
        else {
            L[size]=L[H[r]]; R[L[H[r]]]=size;
            R[size]=H[r]; L[H[r]]=size;
        }
        size++;
    }
    void remove(int c){
        for (int i=D[c]; i!=c; i=D[i])
            L[R[i]]=L[i], R[L[i]]=R[i];
    }
    void resume(int c){
        for (int i=U[c]; i!=c; i=U[i])
            L[R[i]]=R[L[i]]=i;
    }
    int h(){///Óþ«È·¸²¸ÇÈ¥¹ÀËã¼ôÖ¦
        int ret=0;
        bool vis[maxc];
        memset (vis, false, sizeof(vis));
        for (int i=R[0]; i; i=R[i])
        {
            if(vis[i])continue;
            ret++;
            vis[i]=true;
            for (int j=D[i]; j!=i; j=D[j])
                for (int k=R[j]; k!=j; k=R[k])
                    vis[C[k]]=true;
        }
        return ret;
    }
     
    int ans;
    bool Dance(int k){
    	int t=h();                //¸ù¾Ý¾ßÌåÎÊÌâÑ¡ÔñÏÞÖÆËÑË÷Éî¶È»òÖ±½ÓÇó½â¡£  A*Ëã·¨£¬´Ë´¦Ö»Çó×îÓŽâ
        if(k+t>K) return false;
        if(!R[0]){
            return true;
        }
        int c=R[0];
        for (int i=R[0]; i; i=R[i])
            if(S[i]<S[c])c=i;
        for (int i=D[c]; i!=c; i=D[i]){
            remove(i);
            for (int j=R[i]; j!=i; j=R[j])
                remove(j);
            if(Dance(k+1)) return true;
            for (int j=L[i]; j!=i; j=L[j])
                resume(j);
            resume(i);
        }
        return false;
    }
     
    void initL(int x){///col is 1~x,row start from 1
    //	ans=inf;
        for (int i=0; i<=x; ++i){
            S[i]=0;
            D[i]=U[i]=i;
            L[i+1]=i; R[i]=i+1;
        }///¶ÔÁбíÍ·³õʼ»¯
        R[x]=0;
        size=x+1;///ÕæÕýµÄÔªËØ´Óm+1¿ªÊ¼
        memset (H, -1, sizeof(H));
        ///markÿ¸öλÖõÄÃû×Ö
    }
    
    double dist(int i,int j){
    	return sqrt((radar[i].x-cities[j].x)*(radar[i].x-cities[j].x)+(radar[i].y-cities[j].y)*(radar[i].y-cities[j].y));
    }
    
    void BuildLink(double r){
    	for(int i=1;i<=M;i++){
    		for(int j=1;j<=N;j++){
    			if(map[i][j]<=r)
    			Link(i,j);
    		}
    	}
    }
    
    void bin(){
    	double Ans;
    	double l=0,r=2000.0,m;
    	ans=inf;
    	while(l+1e-8<=r){
    		double m=(l+r)/2;
    		ans=inf;
    		initL(N);
    		BuildLink(m);
    		if(Dance(0))
    		{ Ans=m; r=m; }
    		else l=m;
    	}
    	printf("%.6lf
    ",Ans);
    }
    
    
    int main(){
    	int T;
    	scanf("%d",&T);
    	while(T--){
    		scanf("%d%d%d",&N,&M,&K);
    		for(int i=1;i<=N;i++)
    		scanf("%lf%lf",&cities[i].x,&cities[i].y);
    		for(int j=1;j<=M;j++){
    			scanf("%lf%lf",&radar[j].x,&radar[j].y);
    		}
    		for(int i=1;i<=M;i++){
    			for(int j=1;j<=N;j++)
    			map[i][j]=dist(i,j);
    		}
    		bin();
    	}
    	return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/jie-dcai/p/4345537.html
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