zoukankan      html  css  js  c++  java
  • mysql单表操作与多表操作

    
    	0. null和notnull:
    		使用null的时候:
    
    			create table t8(
    
    				id int auto_increment primary key,
    				name varchar(32),
    				email varchar(32)
    			)charset=utf8;
    
    			insert into t8 (email) values ('xxxx');
    
    			mysql> insert into t8 (email) values ('xxxx');
    			Query OK, 1 row affected (0.05 sec)
    
    			mysql> select * from t8;
    			+----+------+-------+
    			| id | name | email |
    			+----+------+-------+
    			|  1 | NULL | xxxx  |
    			+----+------+-------+
    			1 row in set (0.00 sec)
    
    			mysql> select * from t8 where name='';
    			Empty set (0.00 sec)
    
    			mysql> select * from t8 where name is null;
    			+----+------+-------+
    			| id | name | email |
    			+----+------+-------+
    			|  1 | NULL | xxxx  |
    			+----+------+-------+
    			1 row in set (0.01 sec)
    
    
    		使用 notnull的时候:
    			create table t9(
    
    				id int auto_increment primary key,
    				name varchar(32) not null default '',
    				email varchar(32) not null default ''
    			)charset=utf8;
    
    			insert into t9 (email) values ('xxxx');
    
    			mysql> insert into t9 (email) values ('xxxx');
    			Query OK, 1 row affected (0.03 sec)
    
    			mysql> select * from t9;
    			+----+------+-------+
    			| id | name | email |
    			+----+------+-------+
    			|  1 |      | xxxx  |
    			+----+------+-------+
    			1 row in set (0.00 sec)
    
    			mysql> select * from t9 where name='';
    			+----+------+-------+
    			| id | name | email |
    			+----+------+-------+
    			|  1 |      | xxxx  |
    			+----+------+-------+
    			1 row in set (0.00 sec)
    
    
    	1.单表操作 (******************)
    		分组:
    
    			- group by
    				a、分组指的是:将所有记录按照某个相同字段进行归类,比如针对员工信息表的职位分组,或者按照性别进行分组等
    				用法:
    					select 聚合函数, 选取的字段 from  employee group by 分组的字段;
    
    					group by : 是分组的关键词
    					group by 必须和 聚合函数(count) 出现
    
    					where 条件语句和groupby分组语句的先后顺序:
    						where > group by > having(*********)
    
    				例子:
    
    					1. 以性别为例, 进行分组, 统计一下男生和女生的人数是多少个:
    
    						select count(id), gender from  employee group by gender;
    						+-----------+--------+
    						| count(id) | gender |
    						+-----------+--------+
    						|        10 | male   |
    						|         8 | female |
    						+-----------+--------+
    						2 rows in set (0.00 sec)
    
    						mysql> select gender, count(id) as total from  employee group by gender;
    						+--------+-------+
    						| gender | total |
    						+--------+-------+
    						| male   |    10 |
    						| female |     8 |
    						+--------+-------+
    						2 rows in set (0.00 sec)
    
    					2. 对部门进行分组, 求出每个部门年龄最大的那个人?
    						mysql> select depart_id,max(age) from employee group by depart_id;
    						+-----------+----------+
    						| depart_id | max(age) |
    						+-----------+----------+
    						|         1 |       81 |
    						|         2 |       48 |
    						|         3 |       28 |
    						+-----------+----------+
    						3 rows in set (0.01 sec)
    
    					3. min : 求最小的
    
    					4. sum : 求和
    					5. count : 计数 数量
    
    					count 和 sum的区别:
    					mysql> select depart_id,count(age) from employee group by depart_id;
    					+-----------+------------+
    					| depart_id | count(age) |
    					+-----------+------------+
    					|         1 |          8 |
    					|         2 |          5 |
    					|         3 |          5 |
    					+-----------+------------+
    					3 rows in set (0.00 sec)
    
    					mysql> select depart_id,sum(age) from employee group by depart_id;
    					+-----------+----------+
    					| depart_id | sum(age) |
    					+-----------+----------+
    					|         1 |      362 |
    					|         2 |      150 |
    					|         3 |      100 |
    					+-----------+----------+
    					3 rows in set (0.03 sec)
    
    					6. avg : 平均数
    
    
    			- having
    
    				表示对group by 之后的数据, 进行再一次的二次筛选
    
    				mysql> select depart_id,avg(age) from employee group by depart_id ;
    				+-----------+----------+
    				| depart_id | avg(age) |
    				+-----------+----------+
    				|         1 |  45.2500 |
    				|         2 |  30.0000 |
    				|         3 |  20.0000 |
    				+-----------+----------+
    				3 rows in set (0.00 sec)
    
    				mysql> select depart_id,avg(age) from employee group by depart_id having avg(age) > 35;
    				+-----------+----------+
    				| depart_id | avg(age) |
    				+-----------+----------+
    				|         1 |  45.2500 |
    				+-----------+----------+
    				1 row in set (0.00 sec)
    
    				mysql> select depart_id,avg(age) as pj from employee group by depart_id having pj > 35;
    				+-----------+---------+
    				| depart_id | pj      |
    				+-----------+---------+
    				|         1 | 45.2500 |
    				+-----------+---------+
    				1 row in set (0.00 sec)
    
    				where 条件语句和groupby分组语句的先后顺序:
    
    					where > group by > having(*********)
    
    
    		升序 降序
    
    			order by
    
    				order by 字段名 asc (升序) desc(降序)
    
    				如果对多个字段进行排序,
    				比如:
    					age desc, id asc;
    					表示: 先对age进行降序, 如果age有相同的行, 则对id进行升序
    
    				 select * from employee order by age desc, id desc;
    				+----+------------+--------+-----+------------+----------------------------+--------------+------------+--------+-----------+
    				| id | name       | gender | age | hire_date  | post                       | post_comment | salary     | office | depart_id |
    				+----+------------+--------+-----+------------+----------------------------+--------------+------------+--------+-----------+
    				|  3 | wupeiqi    | male   |  81 | 2013-03-05 | teacher                    | NULL         |    8300.00 |    401 |         1 |
    				|  2 | alex       | male   |  78 | 2015-03-02 | teacher                    | NULL         | 1000000.31 |    401 |         1 |
    				|  4 | yuanhao    | male   |  73 | 2014-07-01 | teacher                    | NULL         |    3500.00 |    401 |         1 |
    				|  9 | 歪歪       | female |  48 | 2015-03-11 | sale                       | NULL         |    3000.13 |    402 |         2 |
    				|  8 | 成龙       | male   |  48 | 2010-11-11 | teacher                    | NULL         |   10000.00 |    401 |         1 |
    				| 10 | 丫丫       | female |  38 | 2010-11-01 | sale                       | NULL         |    2000.35 |    402 |         2 |
    				| 14 | 张野       | male   |  28 | 2016-03-11 | operation                  | NULL         |   10000.13 |    403 |         3 |
    				| 13 | 格格       | female |  28 | 2017-01-27 | sale                       | NULL         |    4000.33 |    402 |         2 |
    				|  5 | liwenzhou  | male   |  28 | 2012-11-01 | teacher                    | NULL         |    2100.00 |    401 |         1 |
    				| 18 | 程咬铁     | female |  18 | 2014-05-12 | operation                  | NULL         |   17000.00 |    403 |         3 |
    				| 17 | 程咬铜     | male   |  18 | 2015-04-11 | operation                  | NULL         |   18000.00 |    403 |         3 |
    				| 16 | 程咬银     | female |  18 | 2013-03-11 | operation                  | NULL         |   19000.00 |    403 |         3 |
    				| 15 | 程咬金     | male   |  18 | 1997-03-12 | operation                  | NULL         |   20000.00 |    403 |         3 |
    				| 12 | 星星       | female |  18 | 2016-05-13 | sale                       | NULL         |    3000.29 |    402 |         2 |
    				| 11 | 丁丁       | female |  18 | 2011-03-12 | sale                       | NULL         |    1000.37 |    402 |         2 |
    				|  7 | jinxin     | male   |  18 | 1900-03-01 | teacher                    | NULL         |   30000.00 |    401 |         1 |
    				|  6 | jingliyang | female |  18 | 2011-02-11 | teacher                    | NULL         |    9000.00 |    401 |         1 |
    				|  1 | egon       | male   |  18 | 2017-03-01 | 老男孩驻沙河办事处外交大使 | NULL         |    7300.33 |    401 |         1 |
    				+----+------------+--------+-----+------------+----------------------------+--------------+------------+--------+-----------+
    
    
    		limit
    			分页
    			limit offset, size
    
    			offset: 行数据索引
    			size: 取多少条数据
    
    			mysql> select * from employee limit 0,10;
    				+----+------------+--------+-----+------------+----------------------------+--------------+------------+--------+-----------+
    				| id | name       | gender | age | hire_date  | post                       | post_comment | salary     | office | depart_id |
    				+----+------------+--------+-----+------------+----------------------------+--------------+------------+--------+-----------+
    				|  1 | egon       | male   |  18 | 2017-03-01 | 老男孩驻沙河办事处外交大使 | NULL         |    7300.33 |    401 |         1 |
    				|  2 | alex       | male   |  78 | 2015-03-02 | teacher                    | NULL         | 1000000.31 |    401 |         1 |
    				|  3 | wupeiqi    | male   |  81 | 2013-03-05 | teacher                    | NULL         |    8300.00 |    401 |         1 |
    				|  4 | yuanhao    | male   |  73 | 2014-07-01 | teacher                    | NULL         |    3500.00 |    401 |         1 |
    				|  5 | liwenzhou  | male   |  28 | 2012-11-01 | teacher                    | NULL         |    2100.00 |    401 |         1 |
    				|  6 | jingliyang | female |  18 | 2011-02-11 | teacher                    | NULL         |    9000.00 |    401 |         1 |
    				|  7 | jinxin     | male   |  18 | 1900-03-01 | teacher                    | NULL         |   30000.00 |    401 |         1 |
    				|  8 | 成龙       | male   |  48 | 2010-11-11 | teacher                    | NULL         |   10000.00 |    401 |         1 |
    				|  9 | 歪歪       | female |  48 | 2015-03-11 | sale                       | NULL         |    3000.13 |    402 |         2 |
    				| 10 | 丫丫       | female |  38 | 2010-11-01 | sale                       | NULL         |    2000.35 |    402 |         2 |
    				+----+------------+--------+-----+------------+----------------------------+--------------+------------+--------+-----------+
    				10 rows in set (0.00 sec)
    
    			mysql> select * from employee limit 10,10;
    				+----+--------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
    				| id | name   | gender | age | hire_date  | post      | post_comment | salary   | office | depart_id |
    				+----+--------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
    				| 11 | 丁丁   | female |  18 | 2011-03-12 | sale      | NULL         |  1000.37 |    402 |         2 |
    				| 12 | 星星   | female |  18 | 2016-05-13 | sale      | NULL         |  3000.29 |    402 |         2 |
    				| 13 | 格格   | female |  28 | 2017-01-27 | sale      | NULL         |  4000.33 |    402 |         2 |
    				| 14 | 张野   | male   |  28 | 2016-03-11 | operation | NULL         | 10000.13 |    403 |         3 |
    				| 15 | 程咬金 | male   |  18 | 1997-03-12 | operation | NULL         | 20000.00 |    403 |         3 |
    				| 16 | 程咬银 | female |  18 | 2013-03-11 | operation | NULL         | 19000.00 |    403 |         3 |
    				| 17 | 程咬铜 | male   |  18 | 2015-04-11 | operation | NULL         | 18000.00 |    403 |         3 |
    				| 18 | 程咬铁 | female |  18 | 2014-05-12 | operation | NULL         | 17000.00 |    403 |         3 |
    				+----+--------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
    				8 rows in set (0.00 sec)
    
    
    
    		总结:(***************************)
    			使用的顺序:
    
    				select * from 表名  where 条件 group by 条件 having 条件 order by 条件 limit 条件;
    
    				where > group by > having > order by > limit
    
    
    
    
    	2. 多表操作 (**************************)
    
    		外键
    
    			使用的原因:
    				a. 减少占用的空间
    				b. 只需要修改department表中一次, 其余的表中的数据就会相应的修改
    
    			一对多:
    
    				使用方法:
    					constraint 外键名 foreign key (被约束的字段) references 约束的表(约束的字段)
    
    				create table department(
    					id int auto_increment primary key,
    					name varchar(32) not null default ''
    				)charset utf8;
    
    				insert into department (name) values ('研发部');
    				insert into department (name) values ('运维部');
    				insert into department (name) values ('前台部');
    				insert into department (name) values ('小卖部');
    
    				create table userinfo (
    					id int auto_increment primary key,
    					name varchar(32) not null default '',
    					depart_id int not null default 1,
    
    					constraint fk_user_depart foreign key (depart_id) references department(id),
    					#constraint fk_user_depart foreign key (depart_id) references department(id),
    					#constraint fk_user_depart foreign key (depart_id) references department(id)
    				)charset utf8;
    
    				insert into userinfo (name, depart_id) values ('zekai', 1);
    				insert into userinfo (name, depart_id) values ('xxx', 2);
    				insert into userinfo (name, depart_id) values ('zekai1', 3);
    				insert into userinfo (name, depart_id) values ('zekai2', 4);
    				insert into userinfo (name, depart_id) values ('zekai3', 1);
    				insert into userinfo (name, depart_id) values ('zekai4', 2);
    				insert into userinfo (name, depart_id) values ('zekai4', 5);
    
    
    			多对多:
    				create table boy (
    					id int auto_increment primary key,
    					bname varchar(32) not null default ''
    				)charset utf8;
    
    				insert into boy (bname) values ('zhangsan'),('lisi'),('zhaoliu');
    
    				create table girl (
    					id int auto_increment primary key,
    					gname varchar(32) not null default ''
    				)charset utf8;
    				insert into girl (gname) values ('cuihua'),('gangdan'),('jianguo');
    
    				create table boy2girl (
    					id int auto_increment primary key,
    					bid int not null default 1,
    					gid int not null default 1,
    
    					constraint fk_boy2girl_boy foreign key (bid) references boy(id),
    					constraint fk_boy2girl_girl foreign key (gid) references girl(id)
    				)charset utf8;
    
    				insert into boy2girl (bid, gid) values (1,1),(1,2),(2,3),(3,3),(2,2);
    
    
    				select * from boy left join  boy2girl on boy.id = boy2girl.bid left join girl on girl.id=boy2girl.gid;
    
    				mysql> select * from boy left join  boy2girl on boy.id = boy2girl.bid left join girl on girl.id=boy2girl.gid;
    				+----+----------+------+------+------+------+---------+
    				| id | bname    | id   | bid  | gid  | id   | gname   |
    				+----+----------+------+------+------+------+---------+
    				|  1 | zhangsan |    1 |    1 |    1 |    1 | cuihua  |
    				|  1 | zhangsan |    2 |    1 |    2 |    2 | gangdan |
    				|  2 | lisi     |    5 |    2 |    2 |    2 | gangdan |
    				|  2 | lisi     |    3 |    2 |    3 |    3 | jianguo |
    				|  3 | zhaoliu  |    4 |    3 |    3 |    3 | jianguo |
    				+----+----------+------+------+------+------+---------+
    				5 rows in set (0.00 sec)
    
    				mysql> select bname, gname from boy left join  boy2girl on boy.id = boy2girl.bid left join girl on girl.id=boy2girl.gid;
    				+----------+---------+
    				| bname    | gname   |
    				+----------+---------+
    				| zhangsan | cuihua  |
    				| zhangsan | gangdan |
    				| lisi     | gangdan |
    				| lisi     | jianguo |
    				| zhaoliu  | jianguo |
    				+----------+---------+
    				5 rows in set (0.00 sec)
    
    				mysql> select bname, gname from boy left join  boy2girl on boy.id = boy2girl.bid left join girl on girl.id=boy2girl.gid where bname='zhangsan';
    				+----------+---------+
    				| bname    | gname   |
    				+----------+---------+
    				| zhangsan | cuihua  |
    				| zhangsan | gangdan |
    				+----------+---------+
    				2 rows in set (0.02 sec)
    
    
    			一对一:
    
    				user :
    					id   name  age
    					1    zekai  18
    					2    zhangsan 23
    					3    xxxx   19
    
    				由于salary是比较敏感的字段,因此我们需要将此字段单独拆出来, 变成一张独立的表
    
    				private:
    
    					id  salary   uid  (外键 + unique)
    					1    5000     1
    					2    6000     2
    					3    3000     3
    
    
    				create table user (
    					id int auto_increment primary key,
    					name varchar(32) not null default ''
    				)charset=utf8;
    
    				insert into user (name) values ('zhangsan'),('zekai'),('kkk');
    
    
    				create table priv(
    					id int auto_increment primary key,
    					salary int not null default 0,
    					uid int not null default 1,
    
    					constraint fk_priv_user foreign key (uid) references user(id),
    					unique(uid)
    				)charset=utf8;
    
    				insert into priv (salary, uid) values (2000, 1);
    				insert into priv (salary, uid) values (2800, 2);
    				insert into priv (salary, uid) values (3000, 3);
    
    				insert into priv (salary, uid) values (6000, 1);
    				ERROR 1062 (23000): Duplicate entry '1' for key 'uid'
    
    
    
    		多表联查:
    
    			mysql> select * from department;
    			+----+--------+
    			| id | name   |
    			+----+--------+
    			|  1 | 研发部 |
    			|  2 | 运维部 |
    			|  3 | 前台部 |
    			|  4 | 小卖部 |
    			+----+--------+
    			4 rows in set (0.07 sec)
    
    			mysql> select * from userinfo;
    			+----+--------+-----------+
    			| id | name   | depart_id |
    			+----+--------+-----------+
    			|  1 | zekai  |         1 |
    			|  2 | xxx    |         2 |
    			|  3 | zekai1 |         3 |
    			|  4 | zekai2 |         4 |
    			|  5 | zekai3 |         1 |
    			|  6 | zekai4 |         2 |
    			+----+--------+-----------+
    			6 rows in set (0.00 sec)
    
    			left join 。。。 on
    
    				select * from userinfo left join department on depart_id = department.id
    
    
    				mysql> select name  from userinfo left join department on depart_id = department.id;
    				ERROR 1052 (23000): Column 'name' in field list is ambiguous
    
    				mysql> select userinfo.name as uname, department.name as dname  from userinfo left join department on depart_id = department.id;
    				+--------+--------+
    				| uname  | dname  |
    				+--------+--------+
    				| zekai  | 研发部 |
    				| zekai3 | 研发部 |
    				| xxx    | 运维部 |
    				| zekai4 | 运维部 |
    				| zekai1 | 前台部 |
    				| zekai2 | 小卖部 |
    				+--------+--------+
    				6 rows in set (0.00 sec)
    
    
    
    
    				right join ... on
    
    				mysql> insert into department (name) values ('财务部');
    				Query OK, 1 row affected (0.04 sec)
    
    				mysql>
    				mysql> select * from department;                     );
    				+----+--------+
    				| id | name   |
    				+----+--------+
    				|  1 | 研发部 |
    				|  2 | 运维部 |
    				|  3 | 前台部 |
    				|  4 | 小卖部 |
    				|  5 | 财务部 |
    				+----+--------+
    				5 rows in set (0.00 sec)
    
    				mysql> select * from userinfo;
    				+----+--------+-----------+
    				| id | name   | depart_id |
    				+----+--------+-----------+
    				|  1 | zekai  |         1 |
    				|  2 | xxx    |         2 |
    				|  3 | zekai1 |         3 |
    				|  4 | zekai2 |         4 |
    				|  5 | zekai3 |         1 |
    				|  6 | zekai4 |         2 |
    				+----+--------+-----------+
    				6 rows in set (0.00 sec)
    
    				mysql> select userinfo.name as uname, department.name as dname  from userinfo left join department on depart_id = department.id;
    				+--------+--------+
    				| uname  | dname  |
    				+--------+--------+
    				| zekai  | 研发部 |
    				| zekai3 | 研发部 |
    				| xxx    | 运维部 |
    				| zekai4 | 运维部 |
    				| zekai1 | 前台部 |
    				| zekai2 | 小卖部 |
    				+--------+--------+
    				6 rows in set (0.00 sec)
    
    				mysql> select userinfo.name as uname, department.name as dname  from userinfo right join department on depart_id = department.id;
    				+--------+--------+
    				| uname  | dname  |
    				+--------+--------+
    				| zekai  | 研发部 |
    				| zekai3 | 研发部 |
    				| xxx    | 运维部 |
    				| zekai4 | 运维部 |
    				| zekai1 | 前台部 |
    				| zekai2 | 小卖部 |
    				| NULL   | 财务部 |
    				+--------+--------+
    				7 rows in set (0.00 sec)
    
    
    
    
    
    			inner join
    
    				mysql> select * from department inner join userinfo on department.id=userinfo.depart_id;
    				+----+--------+----+--------+-----------+
    				| id | name   | id | name   | depart_id |
    				+----+--------+----+--------+-----------+
    				|  1 | 研发部 |  1 | zekai  |         1 |
    				|  1 | 研发部 |  5 | zekai3 |         1 |
    				|  2 | 运维部 |  2 | xxx    |         2 |
    				|  2 | 运维部 |  6 | zekai4 |         2 |
    				|  3 | 前台部 |  3 | zekai1 |         3 |
    				|  4 | 小卖部 |  4 | zekai2 |         4 |
    				+----+--------+----+--------+-----------+
    				6 rows in set (0.00 sec)
    
    
  • 相关阅读:
    负载、系统oracle 系统调优之 利用CPUby小雨
    进程、检查oracle 性能调优 解决CPU问题by小雨
    数据、保存【sqlite】——使用记录by小雨
    MySQL中间变量的用法by小雨
    函数、返回Sql Server常用函数之统计、算数、字符串函数by小雨
    数据库、实体数据库设计原则by小雨
    查看、设置centos下在线安装配置mysqlby小雨
    重启、无效Oracle使用raw via lvmby小雨
    总线、虚拟机VMware 创建虚拟机的磁盘操作by小雨
    驱动、数据库Java HIVE 使用Jdbc连接Hiveby小雨
  • 原文地址:https://www.cnblogs.com/jinhongquan/p/11771544.html
Copyright © 2011-2022 走看看