思路:
线段树的基本操作:单点替换,区间最值
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
using namespace std;
#define lhs l, m, rt << 1
#define rhs m + 1, r, rt << 1 | 1
const int maxn = 200010;
int seg[maxn << 2];
void pushUp(int rt)
{
seg[rt] = max(seg[rt << 1], seg[rt << 1 | 1]);
}
void build(int l, int r, int rt)
{
if (l == r)
{
scanf("%d", &seg[rt]);
return;
}
int m = (l + r) >> 1;
build(lhs);
build(rhs);
pushUp(rt);
}
void update(int p, int delta, int l, int r, int rt)
{
if (l == r)
{
seg[rt] = delta;
return;
}
int m = (l + r) >> 1;
if (p <= m)
update(p, delta, lhs);
else
update(p, delta, rhs);
pushUp(rt);
}
int query(int beg, int end, int l, int r, int rt)
{
if (beg <= l && r <= end)
return seg[rt];
int m = (l + r) >> 1;
int ret = 0;
if (beg <= m)
ret = query(beg, end, lhs);
if (end > m)
ret = max(ret, query(beg, end, rhs));
return ret;
}
int main()
{
int n, m;
while (scanf("%d %d", &n, &m) != EOF)
{
build(1, n, 1);
while (m--)
{
char op[16];
int a, b;
scanf("%s", op);
scanf("%d %d", &a, &b);
if (op[0] == 'Q')
printf("%d\n", query(a, b, 1, n, 1));
else if (op[0] == 'U')
update(a, b, 1, n, 1);
}
}
return 0;
}