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  • C# -- 等待异步操作执行完成的方式

    1. 等待异步操作的完成,代码实现

     1 class Program
     2     {
     3         static void Main(string[] args)
     4         {
     5             Func<int, int> mySum1 = SumNumbers;
     6             Func<int, int> mySum2 = SumNumbers;
     7             Func<int, int> mySum3 = SumNumbers;
     8 
     9             AsyncCallback callback = c => Console.WriteLine("线程ID:{0},回调函数执行:{1}",Thread.CurrentThread.ManagedThreadId,c.AsyncState);
    10 
    11 
    12             IAsyncResult result1= mySum1.BeginInvoke(10000, callback, "第一个异步");
    13             IAsyncResult result2= mySum2.BeginInvoke(10000, callback, "第二个异步");
    14             IAsyncResult result3= mySum3.BeginInvoke(10000, callback, "第三个异步");
    15 
    16 
    17             //异步等待方式1:使用EndInvoke
    18             int asyc1 = mySum1.EndInvoke(result1);
    19             Console.WriteLine("第一个异步已经执行完成,结果:{0}",asyc1);
    20 
    21             //异步等待方式2:使用AsyncWaitHandle.WaitOne,参数-1表示一直等待到执行完成
    22             if (result2.AsyncWaitHandle.WaitOne(-1))
    23             {
    24                 Console.WriteLine("第二个异步执行完成");
    25             }
    26 
    27             //异步等待方式3:使用IsCompleted判断
    28             while (!result3.IsCompleted)
    29             {
    30                 Console.WriteLine("第三个异步还在执行中....");
    31                 Thread.Sleep(300);
    32             }
    33             Console.WriteLine("第三个异步执行完成");
    34 
    35             Console.ReadKey();
    36         }
    37 
    38         public static int SumNumbers(int count)
    39         {
    40             int sum = 0;
    41             for (int i = 0; i < count; i++)
    42             {
    43                 sum += i;
    44             }
    45 
    46             Thread.Sleep(3000);
    47             return sum;
    48         }
    49     }

    2. 代码执行结果:

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  • 原文地址:https://www.cnblogs.com/kliine/p/10168334.html
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