zoukankan      html  css  js  c++  java
  • WCF note1

    Summary of WCF

    Client to use service

    1. use ChannelFactory to create proxy to use service. Client code show below.
    using System;
    using System.ServiceModel;
    using Artech.WcfServices.Service.Interface;
    using System.ServiceModel.Channels;
    namespace Artech.WcfServices.Client
    {
        class Program
        {
            static void Main(string[] args)
            {
                using (ChannelFactory<ICalculator> channelFactory = new ChannelFactory<ICalculator>("calculatorservice"))
                {
                    ICalculator calculator = channelFactory.CreateChannel();
                    using (OperationContextScope contextScope = new OperationContextScope(calculator as IClientChannel))
                    {
                        string sn = "{DDA095DA-93CA-49EF-BE01-EF5B47179FD0}";
                        string ns = "http://www.artech.com/";
                        AddressHeader addressHeader = AddressHeader.CreateAddressHeader("sn", ns, sn);
                        MessageHeader messageHeader = addressHeader.ToMessageHeader();
                        OperationContext.Current.OutgoingMessageHeaders.Add(messageHeader);
                        Console.WriteLine("x + y = {2} when x = {0} and y = {1}", 1, 2, calculator.Add(1, 2));
                    }
                }
                Console.Read();
            }
        }
    }
    

    we put our endpoing in config file

    <configuration>
      <system.serviceModel>
        <client>
          <endpoint name="calculatorservice"
                    address="http://127.0.0.1:3721/calculatorservice"
                    binding="ws2007HttpBinding"
                    contract="Artech.WcfServices.Service.Interface.ICalculator"/>
          </client>
      </system.serviceModel>
    </configuration>
    
    1. service Contract definition
    using System.ServiceModel;
    namespace Artech.WcfServices.Service.Interface
    {
        [ServiceContract(Name = "CalculatorService", Namespace ="http://www.artech.com/")]
        public interface ICalculator
        {
            [OperationContract]
            double Add(double x, double y);
        }
    }
    
    1. service definition and use host the service
    using Artech.WcfServices.Service.Interface;
    using System.ServiceModel;
    namespace Artech.WcfServices.Service
    {
        [ServiceBehavior(AddressFilterMode = AddressFilterMode.Any)]
        public class CalculatorService : ICalculator
        {
            public double Add(double x, double y)
            {
                return x + y;
            }
        }
    }
    

    service host

      using (ServiceHost host = new ServiceHost(typeof(CalculatorService)))
                {
                    host.Open();
                    Console.Read();
                }
    

    we put our endpoint definition in the config file
    service host config

    <?xml version="1.0" encoding="utf-8" ?>
    <configuration>
        <system.serviceModel>
            <services>
                <service name="Artech.WcfServices.Service.CalculatorService">
                  <endpoint address="http://127.0.0.1:3721/calculatorservice"
                            binding="ws2007HttpBinding"
                            contract="Artech.WcfServices.Service.Interface.ICalculator">
                    <headers>
                      <sn xmlns="http://www.artech.com/">{DDA095DA-93CA-49EF-BE01-EF5B47179FD0}</sn>
                    </headers>
                  </endpoint>
                </service>
            </services>
        </system.serviceModel>
    </configuration>
    

    Linstenuri vs uri

    1. if the listenUriMode of endpoint set to Unique, three answers: 1. if http, the listenUri will add a guid after the Uri; 2. if tcp,and portshare is disable, it will use another port to take as uri. 3. if tcp and portshare is enable, it will use the same uri but add guid after it.
  • 相关阅读:
    [BFS]luogu P2536 [AHOI2005]病毒检测
    AtCoder Regular Contest 116 总结
    NOI online 2021 #1 总结
    博客半复活
    vue2 Bus兄弟组件间传值问题:重复触发和首次未触发
    ant design中table组件的filter,如何在外部控制
    ant design vue 日期排序
    什么是断点续传?前端如何实现文件的断点续传
    主vue前端面试题补充
    P4248 [AHOI2013]差异 题解
  • 原文地址:https://www.cnblogs.com/kongshu-612/p/5554997.html
Copyright © 2011-2022 走看看