zoukankan      html  css  js  c++  java
  • 转 已知两点坐标和半径求圆心坐标程序C++

     
    数学思想:利用圆方程和直线方程
    已知两点坐标和半径求圆心坐标程序  
    #include <iostream>
    #include <fstream>
    #include <cmath>
    
    using namespace std;
    
    ofstream fout;
    
    typedef struct 
    {
        double x;
        double y;
    }Point;
    
    double Y_Coordinates(double x,double y,double k,double x0);//4个参数
    void Circle_Center(Point p1,Point p2,double dRadius);
    bool Data_Validation(Point p1,Point p2,double dRadius);
    void ReadData(Point &p1,Point &p2,double &dRadius);
    
    void main()
    {
        Point p1,p2;
        double dRadius = 0.0;
    
        ReadData(p1,p2,dRadius);
    
        fout.open("Result.txt");
        Circle_Center(p1,p2,dRadius);
        fout.close();
    }
    
    void Circle_Center(Point p1,Point p2,double dRadius)
    {
        double k = 0.0,k_verticle = 0.0;
        double mid_x = 0.0,mid_y = 0.0;
        double a = 1.0;
        double b = 1.0;
        double c = 1.0;
        Point center1,center2;
        k = (p2.y - p1.y) / (p2.x - p1.x);
        if(k == 0)
        {
            center1.x = (p1.x + p2.x) / 2.0;
            center2.x = (p1.x + p2.x) / 2.0;
            center1.y = p1.y + sqrt(dRadius * dRadius -(p1.x - p2.x) * (p1.x - p2.x) / 4.0);
            center2.y = p2.y - sqrt(dRadius * dRadius -(p1.x - p2.x) * (p1.x - p2.x) / 4.0);
        }
        else
        {
            k_verticle = -1.0 / k;
            mid_x = (p1.x + p2.x) / 2.0;
            mid_y = (p1.y + p2.y) / 2.0;
            a = 1.0 + k_verticle * k_verticle;
            b = -2 * mid_x - k_verticle * k_verticle * (p1.x + p2.x);
            c = mid_x * mid_x + k_verticle * k_verticle * (p1.x + p2.x) * (p1.x + p2.x) / 4.0 - 
                (dRadius * dRadius - ((mid_x - p1.x) * (mid_x - p1.x) + (mid_y - p1.y) * (mid_y - p1.y)));
            
            center1.x = (-1.0 * b + sqrt(b * b -4 * a * c)) / (2 * a);
            center2.x = (-1.0 * b - sqrt(b * b -4 * a * c)) / (2 * a);
            center1.y = Y_Coordinates(mid_x,mid_y,k_verticle,center1.x);
            center2.y = Y_Coordinates(mid_x,mid_y,k_verticle,center2.x);
        }
    
        fout << center1.x << "    " << center1.y << endl;
        fout << center2.x << "    " << center2.y << endl;
    }
    
    double Y_Coordinates(double x,double y,double k,double x0)
    {
        return k * x0 - k * x + y;
    }
    
    bool Data_Validation(Point p1,Point p2,double dRadius)
    {
        double dDistance = 0.0;
        dDistance = sqrt((p1.x - p2.x) * (p1.x - p2.x) + (p1.y - p2.y) * (p1.y - p2.y));
        if(dDistance == 0.0)
        {
            cout << "
    输入了相同的点!
    ";
            return false;
        }
        if((2 * dRadius) >= dDistance)
            return true;
        else
        {
            cout << "
    两点间距离大于直径!
    ";
            return false;
        }
    }
    
    void ReadData(Point &p1,Point &p2,double &dRadius)
    {
        cout << "请输入圆周上一点的坐标:";
        cin >> p1.x >> p1.y;
        cout << "请输入圆周上另一点的坐标:";
        cin >> p2.x >> p2.y;
        cout << "请输入圆的半径:";
        cin >> dRadius;
    
        if(! Data_Validation(p1,p2,dRadius))
        {
            cout << endl << "数据不合理!
    ";
            exit(0);
        }
    }
    View Code
  • 相关阅读:
    dapi 基于Django的轻量级测试平台七 怎样部署到生产环境
    dapi 基于Django的轻量级测试平台六 怎样使用压测功能
    dapi 基于Django的轻量级测试平台五 测试报告
    dapi 基于Django的轻量级测试平台四 任务设置
    【Spark 内核】 Spark 内核解析-上
    【数据结构与算法】—— 插入排序
    大数据框架开发基础之Sqoop(1) 入门
    【数据结构与算法】—— 二分查找
    【数据结构与算法】—— 插入排序
    【数据结构与算法】—— 选择排序
  • 原文地址:https://www.cnblogs.com/lhuan/p/5753847.html
Copyright © 2011-2022 走看看