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  • HUAS 1480 虫洞(最短路)

    把每个点拆成两个点,分别表示黑洞和白洞,然后按题意模拟加边跑最短路即可。

    # include <cstdio>
    # include <cstring>
    # include <cstdlib>
    # include <iostream>
    # include <vector>
    # include <queue>
    # include <stack>
    # include <map>
    # include <set>
    # include <cmath>
    # include <algorithm>
    using namespace std;
    # define lowbit(x) ((x)&(-x))
    # define pi 3.1415926535
    # define eps 1e-9
    # define MOD 1000000007
    # define INF 1000000000
    # define mem(a,b) memset(a,b,sizeof(a))
    # define FOR(i,a,n) for(int i=a; i<=n; ++i)
    # define FO(i,a,n) for(int i=a; i<n; ++i)
    # define bug puts("H");
    # define lch p<<1,l,mid
    # define rch p<<1|1,mid+1,r
    # define mp make_pair
    # define pb push_back
    typedef pair<int,int> PII;
    typedef vector<int> VI;
    # pragma comment(linker, "/STACK:1024000000,1024000000")
    typedef long long LL;
    int Scan() {
        int res=0, flag=0;
        char ch;
        if((ch=getchar())=='-') flag=1;
        else if(ch>='0'&&ch<='9') res=ch-'0';
        while((ch=getchar())>='0'&&ch<='9')  res=res*10+(ch-'0');
        return flag?-res:res;
    }
    void Out(int a) {
        if(a<0) {putchar('-'); a=-a;}
        if(a>=10) Out(a/10);
        putchar(a%10+'0');
    }
    const int N=5005;
    //Code begin...
    
    
    int w[N], mark[N], s[N], dist[N<<1];
    struct qnode{
        int v, c;
        qnode(int _v=0, int _c=0):v(_v),c(_c){}
        bool operator <(const qnode &r)const{return c>r.c;}
    };
    struct Edge{
        int v, cost;
        Edge(int _v=0, int _cost=0):v(_v),cost(_cost){}
    };
    vector<Edge>E[N<<1];
    bool vis[N<<1];
    priority_queue<qnode>que;
    
    void Dijkstra(int n, int start){
        mem(vis,0);
        FOR(i,1,n) dist[i]=INF;
        dist[start]=0; que.push(qnode(start,0));
        qnode tmp;
        while (!que.empty()) {
            tmp=que.top(); que.pop();
            int u=tmp.v;
            if (vis[u]) continue;
            vis[u]=true;
            FO(i,0,E[u].size()) {
                int v=E[u][i].v, cost=E[u][i].cost;
                if (!vis[v]&&dist[v]>dist[u]+cost) dist[v]=dist[u]+cost, que.push(qnode(v,dist[v]));
            }
        }
    }
    void addedge(int u, int v, int w){E[u].pb(Edge(v,w));}
    int main ()
    {
        int n, m, u, v, cost;
        scanf("%d%d",&n,&m);
        FOR(i,1,n) scanf("%d",mark+i);
        FOR(i,1,n) scanf("%d",w+i);
        FOR(i,1,n) scanf("%d",s+i), addedge(i,n+i,0), addedge(n+i,i,s[i]);
        FOR(i,1,m) {
            scanf("%d%d%d",&u,&v,&cost);
            if (mark[u]==mark[v]) addedge(u,n+v,cost), addedge(n+u,v,cost);
            else {
                int delta=abs(w[u]-w[v]);
                addedge(u,v,max(0,cost-delta)); addedge(n+u,n+v,cost+delta);
            }
        }
        Dijkstra(n<<1,mark[1]?n+1:1);
        printf("%d
    ",min(dist[n],dist[n<<1]));
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/lishiyao/p/6628980.html
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