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  • dijkstra和dijkstra堆优化模板

    dijkstra和dijkstra堆优化模板

    之前QAQ一直没有准备堆优化模板,本例以PAT A1003为例,整理dijkstra和dijkstra堆优化模板

    Dijkstra

    我们可以发现该篇幅找最小值部分是使用量一个for循环

    #include <iostream>
    #include <algorithm>
    using namespace std;
    int n, m, c1, c2;
    int edge[510][510], weight[510], dis[510], num[510], w[510];
    bool vis[510];
    const int inf = 99999999;
    int main() {
        scanf("%d%d%d%d", &n, &m, &c1, &c2);
        for(int i = 0; i < n; i++)
            scanf("%d", &weight[i]);
        fill(edge[0], edge[0] + 510 * 510, inf);
        fill(dis, dis + 510, inf);
        int a, b, c;
        for(int i = 0; i < m; i++){
            scanf("%d%d%d", &a, &b, &c);
            edge[a][b] = edge[b][a] = c;
        }
        dis[c1] = 0;
        w[c1] = weight[c1];
        num[c1] = 1;
        while(true) {
            int u = -1, minn = inf;
            for(int j = 0; j < n; j++){
                if(vis[j] == false && dis[j] < minn) {
                    u = j;
                    minn = dis[j];
                }
            }
            if(u == -1) break;
            vis[u] = true;
            for(int  v = 0; v < n; v++) {
                if(vis[v] == false && edge[u][v] != inf) {
                    if(dis[u] + edge[u][v] < dis[v]) {
                        dis[v] = dis[u] + edge[u][v];
                        num[v] = num[u];
                        w[v] = w[u] + weight[v];
                    }else if(dis[u] + edge[u][v] == dis[v]) {
                        num[v] = num[v] + num[u];
                        if(w[u] + weight[v] > w[v])
                            w[v] = w[u] + weight[v];
                    }
                }
            }
        }
        printf("%d %d", num[c2], w[c2]);
        return 0;
    }
    

    dijkstra堆优化

    我们在找最小值那部分进行替换成堆即可

    #include <iostream>
    #include <queue>
    #include <algorithm>
    using namespace std;
    int n, m, c1, c2;
    int edge[510][510], weight[510], dis[510], num[510], w[510];
    bool vis[510];
    const int inf = 99999999;
    priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> q;
    int main() {
        scanf("%d%d%d%d", &n, &m, &c1, &c2);
        for(int i = 0; i < n; i++)
            scanf("%d", &weight[i]);
        fill(edge[0], edge[0] + 510 * 510, inf);
        fill(dis, dis + 510, inf);
        int a, b, c;
        for(int i = 0; i < m; i++){
            scanf("%d%d%d", &a, &b, &c);
            edge[a][b] = edge[b][a] = c;
        }
        dis[c1] = 0;
        w[c1] = weight[c1];
        num[c1] = 1;
        q.push({0, c1});
        while(q.size()) {
            // 改为了弹出
            int u = q.top().second;
            q.pop();
            // 如果已经访问,这边记得进行continue操作
            if(vis[u]) continue;
            vis[u] = true;
            for(int  v = 0; v < n; v++) {
                if(vis[v] == false && edge[u][v] != inf) {
                    if(dis[u] + edge[u][v] < dis[v]) {
                        dis[v] = dis[u] + edge[u][v];
                        num[v] = num[u];
                        w[v] = w[u] + weight[v];
                    }else if(dis[u] + edge[u][v] == dis[v]) {
                        num[v] = num[v] + num[u];
                        if(w[u] + weight[v] > w[v])
                            w[v] = w[u] + weight[v];
                    }
                    q.push({dis[v], v});
                }
            }
        }
        printf("%d %d", num[c2], w[c2]);
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/littlepage/p/13079770.html
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