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  • hdu 1108 最小公倍数

    最小公倍数

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 24145    Accepted Submission(s): 13180


    Problem Description
    给定两个正整数,计算这两个数的最小公倍数。
     
    Input
    输入包含多组测试数据,每组只有一行,包括两个不大于1000的正整数.
     
    Output
    对于每个测试用例,给出这两个数的最小公倍数,每个实例输出一行。
     
    Sample Input
    10 14
     
    Sample Output
    70
     
    Source
     
     1 #include <iostream>
     2 #include <cmath>
     3 #include <cstdio>
     4 #include <cstring>
     5 #include <cstdlib>
     6 using namespace std;
     7 int gcd(int a, int b){
     8   return b == 0 ? a : gcd(b, a%b);
     9 }
    10 int main(void){
    11   int a, b;
    12 #ifndef ONLINE_JUDGE
    13   freopen("1108.in", "r", stdin);
    14 #endif
    15   while (~scanf("%d%d", &a, &b)){
    16     printf("%d\n", a * b / gcd(a, b));
    17   }
    18   return 0;
    19 }

    基础的数学题……

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  • 原文地址:https://www.cnblogs.com/liuxueyang/p/2955691.html
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