zoukankan      html  css  js  c++  java
  • 1344. Angle Between Hands of a Clock (M)

    Angle Between Hands of a Clock (M)

    题目

    Given two numbers, hour and minutes. Return the smaller angle (in degrees) formed between the hour and the minute hand.

    Example 1:

    img
    Input: hour = 12, minutes = 30
    Output: 165
    

    Example 2:

    img
    Input: hour = 3, minutes = 30
    Output: 75
    

    Example 3:

    img

    Input: hour = 3, minutes = 15
    Output: 7.5
    

    Example 4:

    Input: hour = 4, minutes = 50
    Output: 155
    

    Example 5:

    Input: hour = 12, minutes = 0
    Output: 0
    

    Constraints:

    • 1 <= hour <= 12
    • 0 <= minutes <= 59
    • Answers within 10^-5 of the actual value will be accepted as correct.

    题意

    计算时钟时针和分针的夹角。

    思路

    数学计算题。


    代码实现

    Java

    class Solution {
        public double angleClock(int hour, int minutes) {
            double angleM = 6.0 * minutes;
            double angleH = 30.0 * hour + 30.0 * minutes / 60;
            double angle = Math.abs(angleM - angleH);
            return angle > 180 ? 360 - angle : angle;
        }
    }
    
  • 相关阅读:
    凤凰传奇
    信息孤岛
    别了,中珠
    吃苦要趁早
    触动——beyond歌词
    走出舒适区,迎接挑战
    创新永存
    信息时代
    变色龙时代——创新
    Java基本的数据类型
  • 原文地址:https://www.cnblogs.com/mapoos/p/13303394.html
Copyright © 2011-2022 走看看