Range Sum of BST (E)
题目
Given the root
node of a binary search tree, return the sum of values of all nodes with a value in the range [low, high]
.
Example 1:
Input: root = [10,5,15,3,7,null,18], low = 7, high = 15
Output: 32
Example 2:
Input: root = [10,5,15,3,7,13,18,1,null,6], low = 6, high = 10
Output: 23
Constraints:
- The number of nodes in the tree is in the range
[1, 2 * 10^4]
. 1 <= Node.val <= 10^5
1 <= low <= high <= 10^5
- All
Node.val
are unique.
题意
求树中所有在指定范围内的值得和。
思路
DFS即可。
代码实现
Java
class Solution {
public int rangeSumBST(TreeNode root, int low, int high) {
if (root == null) {
return 0;
}
int sum = root.val >= low && root.val <= high ? root.val : 0;
return sum + rangeSumBST(root.left, low, high) + rangeSumBST(root.right, low, high);
}
}