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  • 动态规划——Freedom Trail

    题目:https://leetcode.com/problems/freedom-trail/

    额。。。不解释大意了,题目我也不想写过程了有点繁琐,直接给出代码:

     1 public int findRotateSteps(String ring, String key) {
     2         int rlen = ring.length();
     3         int klen = key.length();
     4         int[][]dp = new int[klen+1][rlen+1];
     5         int temp = 0,step = 0,diff = 0;
     6         for(int i = 0;i<=klen;i++) {
     7             for(int j = 1;j<=rlen;j++)
     8                 if(i==0)dp[i][j] = 0;
     9                 else dp[i][j] = Integer.MAX_VALUE;
    10         }
    11         for(int i = 1;i<=klen;i++) {
    12             for(int j = 1;j<=rlen;j++) {
    13                 temp = Integer.MAX_VALUE;
    14                 if(ring.charAt(j-1)==key.charAt(i-1)) {
    15                     if(i==1)temp = Math.min(j-1,rlen+1-j);
    16                     else {
    17                         for(int k = 1;k<=rlen;k++)
    18                             if(dp[i-1][k]!=Integer.MAX_VALUE) {
    19                                 diff = Math.abs(j-k);
    20                                 step = Math.min(diff,rlen-diff);
    21                                 temp = Math.min(temp,step+dp[i-1][k]);
    22                             }
    23                     }
    24                 }
    25                 dp[i][j] = temp;
    26             }
    27         }
    28         /*
    29         for(int i = 1;i<=klen;i++) {
    30             for(int j = 1;j<=rlen;j++)
    31                 System.out.print(dp[i][j]+" ");
    32             System.out.println();
    33         }*/
    34         int ans = dp[klen][1];
    35         for(int i = 2;i<=rlen;i++) {
    36             ans = ans < dp[klen][i]?ans:dp[klen][i];
    37         }
    38         return ans+klen;
    39     }
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  • 原文地址:https://www.cnblogs.com/messi2017/p/9943694.html
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