A1082 Read Number in Chinese (25 分)

1082 Read Number in Chinese (25 分)

 

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fu first if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu. Note: zero (ling) must be handled correctly according to the Chinese tradition. For example, 100800 is yi Shi Wan ling ba Bai.

Input Specification:

Each input file contains one test case, which gives an integer with no more than 9 digits.

Output Specification:

For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.

Sample Input 1:

-123456789

Sample Output 1:

Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu

Sample Input 2:

100800

Sample Output 2:

yi Shi Wan ling ba Bai

#include<bits/stdc++.h>
using namespace std;

string Week[7]={
    "MON","TUE","WED","THU","FRI","SAT","SUN"
};

string num[10]={
    "ling","yi","er","san","si","wu","liu","qi","ba","jiu"
};

string wei[5]={
    "Shi","Bai","Qian","Wan","Yi"
};




int main(){
    
    string str;
    
    cin>>str;
    
    int len=str.size();
    
    int left=0,right=len-1;
    
    
    if(str[0]=='-')
    {
        left++;
        cout<<"Fu";
    }
    
    while(left+4<=right)   //注意等于号
            right-=4;
    
    
    while(left<len){
            
        bool flag=false;
        bool isPrint=false;
        
        while(left<=right){
        
            
            if(left>0&&str[left]=='0'){
                flag=true;
            }else{
                if(flag){
                    cout<<" ling";
                    flag=false;
                }
                isPrint=true;
                
                if(left>0)cout<<" ";  //注意格式空格
                cout<<num[str[left]-'0'];
                
                if(left!=right)
                    cout<<" "<<wei[right-left-1];
                    
            }
            
            left++;    
        }
        
        
        if(isPrint==true&&right!=len-1){
            cout<<" "<<wei[(len-1-right)/4+2];
        }
            
        
        right+=4;
        
        
    }
    
    
    
    return 0;
}