zoukankan      html  css  js  c++  java
  • Quicksum

    Quicksum

    Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 447 Accepted Submission(s): 339
    Problem Description
    A checksum is an algorithm that scans a packet of data and returns a single number. The idea is that if the packet is changed, the checksum will also change, so checksums are often used for detecting transmission errors, validating document contents, and in many other situations where it is necessary to detect undesirable changes in data.

    For this problem, you will implement a checksum algorithm called Quicksum. A Quicksum packet allows only uppercase letters and spaces. It always begins and ends with an uppercase letter. Otherwise, spaces and letters can occur in any combination, including consecutive spaces.

    A Quicksum is the sum of the products of each character's position in the packet times the character's value. A space has a value of zero, while letters have a value equal to their position in the alphabet. So, A=1, B=2, etc., through Z=26. Here are example Quicksum calculations for the packets "ACM" and "MID CENTRAL":

    ACM: 1*1 + 2*3 + 3*13 = 46MID CENTRAL: 1*13 + 2*9 + 3*4 + 4*0 + 5*3 + 6*5 + 7*14 + 8*20 + 9*18 + 10*1 + 11*12 = 650
     
    Input
    The input consists of one or more packets followed by a line containing only # that signals the end of the input. Each packet is on a line by itself, does not begin or end with a space, and contains from 1 to 255 characters.
     
    Output
    For each packet, output its Quicksum on a separate line in the output.

     
    Sample Input
    ACM
    MID CENTRAL
    REGIONAL PROGRAMMING CONTEST
    ACN
    A C M
    ABC
    BBC
    #
     
    Sample Output
    46
    650
    4690
    49
    75
    14
    15
    #include <iostream>
    #include "stdio.h"
    #include "string.h"
    #include "ctype.h"
    using namespace std;
    
    int main()
    {
        char c[255];
        int total;
        while(gets(c)&&c[0]!='#')
        {
            total = 0 ;
            for(int j = 0 ; j < strlen(c) ; j++)
            {
                if(c[j]!=' ')
                total +=(((int)c[j]-64)*(j+1));
            }
            cout<<total<<endl;
        }
        return 0;
    }
  • 相关阅读:
    Docker Swarm(十)Portainer 集群可视化管理
    Docker Swarm(九)资源限制
    Docker Swarm(八)滚动更新、回滚服务
    Docker Swarm(七)Scale 扩(缩)容服务
    Docker Swarm(六)Label 节点标签与服务约束
    Docker Swarm(五)Config 配置管理
    select样式调整
    在VS2008和VS2010中禁用Visual Assist X
    解决IE与FF 中 input focus 光标移动在最后的方案
    Office Web APP预览如何去掉顶部版权标志“Microsoft Office Web Apps”
  • 原文地址:https://www.cnblogs.com/newpanderking/p/2114914.html
Copyright © 2011-2022 走看看