zoukankan      html  css  js  c++  java
  • 希尔排序(Java实现)

    基本希尔排序,步长为2

    public class ShellSort {
    
        public static <T extends Comparable<? super T>> void sort(T[] arr) {
            for (int len = arr.length, step = len / 2; step >= 1; step /= 2) {
                for (int i = step; i < len; i++) {
                    T temp = arr[i];
                    int j = i - step;
                    for (;j >= 0 && arr[j].compareTo(temp) > 0; j -= step) {
                        arr[j + step] = arr[j];
                    }
                    arr[j + step] = temp;
                }
            }
        }
    
        public static void swap(Object arr[], int i, int j) {
            if (i != j) {
                Object temp = arr[i];
                arr[i] = arr[j];
                arr[j] = temp;
            }
        }
    
        private static void printArr(Object[] arr) {
            for (Object o : arr) {
                System.out.print(o);
                System.out.print("\t");
            }
            System.out.println();
        }
    
        public static void main(String args[]) {
            Integer[] arr = {3, 5, 1, 7, 2, 9, 8, 0, 4, 6};
            printArr(arr);//3   5   1   7   2   9   8   0   4   6
            sort(arr);
            printArr(arr);//0   1   2   3   4   5   6   7   8   9
        }
    }
    

     

    希尔排序,步长为 【1, 4, 13, 40, 121, 364, 1093, ...】

    public class ShellSort {
    
        public static <T extends Comparable<? super T>> void sort2(T[] arr) {
            for (int len = arr.length, step = len / 2; step >= 1; step /= 2) {
                for (int i = step; i < len; i++) {
                    T temp = arr[i];
                    int j = i - step;
                    for (; j >= 0 && arr[j].compareTo(temp) > 0; j -= step) {
                        arr[j + step] = arr[j];
                    }
                    arr[j + step] = temp;
                }
            }
        }
    
        public static <T extends Comparable<? super T>> void sort(T[] arr) {
            int len = arr.length;
            int step = 1;
            while (step < len / 3) {
                step = step * 3 + 1;
            }
            for (; step >= 1; step /= 3) {
                for (int i = step; i < len; i++) {
                    T temp = arr[i];
                    int j = i - step;
                    for (; j >= 0 && arr[j].compareTo(temp) > 0; j -= step) {
                        arr[j + step] = arr[j];
                    }
                    arr[j + step] = temp;
                }
            }
        }
    
    
        public static void swap(Object arr[], int i, int j) {
            if (i != j) {
                Object temp = arr[i];
                arr[i] = arr[j];
                arr[j] = temp;
            }
        }
    
        private static void printArr(Object[] arr) {
            for (Object o : arr) {
                System.out.print(o);
                System.out.print("\t");
            }
            System.out.println();
        }
    
        public static void main(String args[]) {
            Integer[] arr = {3, 5, 1, 7, 2, 9, 8, 0, 4, 6};
            printArr(arr);//3   5   1   7   2   9   8   0   4   6
            sort(arr);
            printArr(arr);//0   1   2   3   4   5   6   7   8   9
        }
    }
    

      

    ---------------------------------------------------------
    学如不及,犹恐失之
  • 相关阅读:
    Java微信分享接口开发
    lintcode 刷题 by python 部分链表题总结(2)
    基于CART的回归和分类任务
    机器学习: K-means 聚类
    python 中的堆 (heapq 模块)应用:Merge K Sorted Lists
    名人、皇家谱系
    python实现数组和链表的归并排序
    Python 正则 —— 捕获与分组
    ArcGIS中的数据连接问题——数据类型不统一
    Spring boot 搭建
  • 原文地址:https://www.cnblogs.com/noKing/p/7911834.html
Copyright © 2011-2022 走看看