题目:
Given a string containing just the characters '('
, ')'
, '{'
, '}'
, '['
and ']'
, determine if the input string is valid.
The brackets must close in the correct order, "()"
and "()[]{}"
are all valid but "(]"
and "([)]"
are not.
思路:
用栈来解决。
package ds; import java.util.Stack; public class ValidParentheses { public boolean isValid(String s) { Stack<Character> stack = new Stack<Character>(); int len = s.length(); for (int i = 0; i < len; ++i) { char c = s.charAt(i); switch (c) { case '(': case '[': case '{': stack.push(c); break; case ')': if (stack.isEmpty() || stack.pop() != '(') return false; break; case ']': if (stack.isEmpty() || stack.pop() != '[') return false; break; case '}': if (stack.isEmpty() || stack.pop() != '{') return false; break; } } return stack.isEmpty(); } public static void main(String[] args) { // TODO Auto-generated method stub ValidParentheses v = new ValidParentheses(); // Test case 1 System.out.println(v.isValid("()[]}")); // Test case 2 System.out.println(v.isValid("(")); } }