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  • HDU3726---Graph and Queries 离线处理+Treap

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3726

    题意:n个点m条边的一张无向图,每个点有一个权值, 有3中操作。

    D X 删除第X条边

    Q X K 计算与X点相连所有点中第k大的权值

    C X V把X的权值改为 V

    输出 Q次询问的平均值

    大白上的例题, 离线处理,把所有操作 反过来处理,,这样删边变成了 加边,,瞬间好处理多了。。细节也有很多。

      1 #include <set>
      2 #include <map>
      3 #include <cmath>
      4 #include <ctime>
      5 #include <queue>
      6 #include <stack>
      7 #include <cstdio>
      8 #include <string>
      9 #include <vector>
     10 #include <cstdlib>
     11 #include <cstring>
     12 #include <iostream>
     13 #include <algorithm>
     14 using namespace std;
     15 typedef unsigned long long ull;
     16 typedef long long ll;
     17 const int inf = 0x3f3f3f3f;
     18 const double eps = 1e-8;
     19 const int maxn = 2e4+10;
     20 int n, m, val[maxn];
     21 int pa[maxn];
     22 void init()
     23 {
     24     for (int i = 0; i <= n; i++)
     25     {
     26         pa[i] = i;
     27     }
     28 }
     29 int find(int x)
     30 {
     31     return pa[x] = (pa[x] == x ? x : find(pa[x]));
     32 }
     33 struct Node
     34 {
     35     Node* ch[2];
     36     int key, r, siz;
     37     Node (int x)
     38     {
     39         key = x;
     40         siz = 1;
     41         ch[0] = ch[1] = NULL;
     42         r = rand();
     43     }
     44     bool operator < (const Node &rhs)const
     45     {
     46         return r < rhs.r;
     47     }
     48     int cmp(int x)
     49     {
     50         if (x == key)
     51             return -1;
     52         return x < key ? 0 : 1;
     53     }
     54     void maintain()
     55     {
     56         siz = 1;
     57         if (ch[0] != NULL)
     58             siz += ch[0] -> siz;
     59         if (ch[1] != NULL)
     60             siz += ch[1] -> siz;
     61     }
     62 };
     63 void rotate(Node* &root, int d)
     64 {
     65     Node* tmp = root -> ch[d^1];
     66     root -> ch[d^1] = tmp -> ch[d];
     67     tmp -> ch[d] = root;
     68     root -> maintain();
     69     tmp -> maintain();
     70     root = tmp;
     71 }
     72 void insert(Node* &root, int x)
     73 {
     74     if (root == NULL)
     75         root = new Node (x);
     76     else
     77     {
     78         int d = x < root -> key ? 0 : 1;
     79         insert (root ->ch[d], x);
     80         if (root -> ch[d] -> r > root -> r)
     81             rotate(root, d^1);
     82 
     83     }
     84     root -> maintain();
     85 }
     86 void dele(Node* &root, int x)
     87 {
     88     int d = root -> cmp(x);
     89     if (d == -1)
     90     {
     91         Node* tmp = root;
     92         if (root -> ch[0] != NULL && root -> ch[1] != NULL)
     93         {
     94             int d1 = (root -> ch[0] -> r > root -> ch[1] -> r ? 0 : 1);
     95             rotate(root, d1^1);
     96             dele(root -> ch[d1^1], x);
     97         }
     98         else
     99         {
    100             if (root -> ch[0] == NULL)
    101                 root = root -> ch[1];
    102             else
    103                 root = root -> ch[0];
    104             delete tmp;
    105         }
    106     }
    107     else
    108         dele(root->ch[d], x);
    109     if (root != NULL)
    110         root -> maintain();
    111 }
    112 int Get_kth(Node* root, int k)
    113 {
    114     if (root == NULL || k <= 0 || root -> siz < k)
    115         return 0;
    116     int s = root -> ch[1] == NULL ? 0 : root -> ch[1] -> siz;
    117     if (s + 1 == k)
    118         return root -> key;
    119     if (s + 1 > k)
    120         return Get_kth(root -> ch[1], k);
    121     else
    122         return Get_kth(root -> ch[0], k-s-1);
    123 
    124 }
    125 Node* root[maxn];
    126 void merge_tree(Node* &src, Node* &fa)
    127 {
    128     if (src -> ch[0] != NULL)
    129         merge_tree(src -> ch[0], fa);
    130     if (src -> ch[1] != NULL)
    131         merge_tree(src -> ch[1], fa);
    132     insert(fa, src -> key);
    133     delete src;
    134     src = NULL;
    135 }
    136 void remove_tree(Node* &root)
    137 {
    138     if (root -> ch[0] != NULL)
    139         remove_tree(root -> ch[0]);
    140     if (root -> ch[1] != NULL)
    141         remove_tree(root -> ch[1]);
    142     delete root;
    143     root = NULL;
    144 }
    145 struct
    146 {
    147     int x, y;
    148     bool is_del;
    149 } e[3 * maxn];
    150 struct
    151 {
    152     int type, x, p;
    153 } Q[maxn*25];
    154 void add_edge(int idx)
    155 {
    156     int fx = find(e[idx].x);
    157     int fy = find(e[idx].y);
    158     if (fx != fy)
    159     {
    160         if (root[fx] -> siz > root[fy] -> siz)
    161         {
    162             pa[fy] = fx;
    163             merge_tree(root[fy], root[fx]);
    164         }
    165         else
    166         {
    167             pa[fx] = fy;
    168             merge_tree(root[fx], root[fy]);
    169 
    170         }
    171     }
    172 
    173 }
    174 int main(void)
    175 {
    176 #ifndef ONLINE_JUDGE
    177     freopen("in.txt","r",stdin);
    178 #endif
    179     int cas = 1;
    180     while (~ scanf ("%d%d",&n, &m))
    181     {
    182         if (n == 0 && m == 0)
    183             break;
    184         for (int i = 0; i < n; i++)
    185         {
    186             scanf ("%d", val + 1 + i);
    187         }
    188         for (int i = 1; i <= m; i++)
    189         {
    190             scanf ("%d%d", &e[i].x, &e[i].y);
    191             e[i].is_del = false;
    192         }
    193         char op[5];
    194         int tot = 0;
    195         while (scanf ("%s",op) && op[0] != 'E')
    196         {
    197             if (op[0] == 'D')
    198             {
    199                 scanf ("%d", &Q[tot].x);
    200                 Q[tot++].type = 0;
    201                 e[Q[tot-1].x].is_del = true;
    202             }
    203             if (op[0] == 'Q')
    204             {
    205                 scanf ("%d%d", &Q[tot].x, &Q[tot].p);
    206                 Q[tot++].type = 1;
    207             }
    208             if (op[0] == 'C')
    209             {
    210                 int v;
    211                 scanf ("%d%d", &Q[tot].x, &v);
    212                 Q[tot].p = val[Q[tot].x];
    213                 val[Q[tot].x] = v;
    214                 Q[tot++].type = 2;
    215             }
    216         }
    217         init();
    218         for (int i = 0; i < n; i++)
    219         {
    220             if (root[i+1] != NULL)
    221                 remove_tree(root[i+1]);
    222             root[i+1] = new Node (val[i+1]);
    223         }
    224         for (int i = 0; i < m; i++)
    225         {
    226             if (e[i+1].is_del == false)
    227                 add_edge(i+1);
    228         }
    229         ll ans1 = 0, ans2 = 0;
    230         for (int i = tot - 1; i >= 0; i--)
    231         {
    232             if (Q[i].type == 0)
    233             {
    234                 add_edge(Q[i].x);
    235             }
    236             if (Q[i].type == 1)
    237             {
    238                 ans1 += Get_kth(root[find(Q[i].x)], Q[i].p);
    239                 ans2 ++;
    240             }
    241             if (Q[i].type == 2)
    242             {
    243                int father = find(Q[i].x);
    244                 dele (root[father], val[Q[i].x]);
    245                 insert (root[father], Q[i].p);
    246                 val[Q[i].x] = Q[i].p;
    247             }
    248         }
    249         printf("Case %d: %.6f
    ", cas++, 1.0*ans1 / ans2);
    250     }
    251     return 0;
    252 }
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  • 原文地址:https://www.cnblogs.com/oneshot/p/4330751.html
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