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  • 洛谷P3369 普通平衡树

    平衡树板子

    因为之前写spaly删除出了大锅。。所以就去学了一手fhq-treap。。。
    下面是抄来的板子(真香

    #include <bits/stdc++.h>
    #define INF 0x3f3f3f3f
    #define full(a, b) memset(a, b, sizeof a)
    using namespace std;
    typedef long long ll;
    inline int lowbit(int x){ return x & (-x); }
    inline int read(){
        int X = 0, w = 0; char ch = 0;
        while(!isdigit(ch)) { w |= ch == '-'; ch = getchar(); }
        while(isdigit(ch)) X = (X << 3) + (X << 1) + (ch ^ 48), ch = getchar();
        return w ? -X : X;
    }
    inline int gcd(int a, int b){ return a % b ? gcd(b, a % b) : b; }
    inline int lcm(int a, int b){ return a / gcd(a, b) * b; }
    template<typename T>
    inline T max(T x, T y, T z){ return max(max(x, y), z); }
    template<typename T>
    inline T min(T x, T y, T z){ return min(min(x, y), z); }
    template<typename A, typename B, typename C>
    inline A fpow(A x, B p, C lyd){
        A ans = 1;
        for(; p; p >>= 1, x = 1LL * x * x % lyd)if(p & 1)ans = 1LL * x * ans % lyd;
        return ans;
    }
    
    // fhq-treap
    const int N = 100005;
    int tree[N][2], val[N], size[N], rnd[N], tot;
    int p, q, t, root;
    
    void push_up(int x){
        size[x] = size[tree[x][0]] + size[tree[x][1]] + 1;
    }
    
    int merge(int x, int y){
        if(!x || !y) return x + y;
        if(rnd[x] < rnd[y]){
            tree[x][1] = merge(tree[x][1], y);
            push_up(x);
            return x;
        }
        else{
            tree[y][0] = merge(x, tree[y][0]);
            push_up(y);
            return y;
        }
    }
    
    void split(int cur, int k, int &x, int &y){
        if(!cur){ x = 0, y = 0; return; }
        if(val[cur] <= k) x = cur, split(tree[cur][1], k, tree[cur][1], y);
        else y = cur, split(tree[cur][0], k, x, tree[cur][0]);
        push_up(cur);
    }
    
    int rndom(){
        return rand() << 15 | rand();
    }
    
    int newNode(int v){
        size[++tot] = 1, rnd[tot] = rndom(), val[tot] = v;
        return tot;
    }
    
    void insert(int x){
        split(root, x, p, q);
        root = merge(merge(p, newNode(x)), q);
    }
    
    void del(int x){
        split(root, x, p, t);
        split(p, x - 1, p, q);
        q = merge(tree[q][0], tree[q][1]);
        root = merge(merge(p, q), t);
    }
    
    int select(int cur, int k){
        while(1){
            if(size[tree[cur][0]] >= k) cur = tree[cur][0];
            else{
                if(size[tree[cur][0]] + 1 == k) return cur;
                else k = k - size[tree[cur][0]] - 1, cur = tree[cur][1];
            }
        }
    }
    
    int ranks(int x){
        int ret = 0; split(root, x - 1, p, q);
        ret = size[p] + 1;
        merge(p, q);
        return ret;
    }
    
    int successor(int x){
        int ret = 0; split(root, x, p, q);
        ret = val[select(q, 1)];
        root = merge(p, q);
        return ret;
    }
    
    int precursor(int x){
        int ret = 0; split(root, x - 1, p, q);
        ret = val[select(p, size[p])];
        root = merge(p, q);
        return ret;
    }
    
    int main(){
    
        srand(time(0));
        int n = read();
        while(n --){
            int opt = read();
            if(opt == 1) insert(read());
            else if(opt == 2) del(read());
            else if(opt == 3) printf("%d
    ", ranks(read()));
            else if(opt == 4) printf("%d
    ", val[select(root, read())]);
            else if(opt == 5) printf("%d
    ", precursor(read()));
            else printf("%d
    ", successor(read()));
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/onionQAQ/p/10614763.html
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